怎么用python做一个井字棋游戏

以下是一个简单的井字棋游戏的Python代码：

board = {'1': ' ', '2': ' ', '3': ' ', '4': ' ', '5': ' ', '6': ' ', '7': ' ', '8': ' ', '9': ' '}

def print_board(board):
    print(board['1'] + '|' + board['2'] + '|' + board['3'])
    print('-+-+-')
    print(board['4'] + '|' + board['5'] + '|' + board['6'])
    print('-+-+-')
    print(board['7'] + '|' + board['8'] + '|' + board['9'])

def check_win(board, player):
    if (board['1'] == player and board['2'] == player and board['3'] == player) or \
        (board['4'] == player and board['5'] == player and board['6'] == player) or \
        (board['7'] == player and board['8'] == player and board['9'] == player) or \
        (board['1'] == player and board['4'] == player and board['7'] == player) or \
        (board['2'] == player and board['5'] == player and board['8'] == player) or \
        (board['3'] == player and board['6'] == player and board['9'] == player) or \
        (board['1'] == player and board['5'] == player and board['9'] == player) or \
        (board['3'] == player and board['5'] == player and board['7'] == player):
        return True
    else:
        return False

def tic_tac_toe():
    player = 'X'
    count = 0
    while count < 9:
        print_board(board)
        print("It's", player, "turn. Which place do you want to mark?")
        move = input()
        if board[move] == ' ':
            board[move] = player
            count += 1
            if check_win(board, player):
                print_board(board)
                print("Congratulations! Player", player, "wins!")
                return
            if player == 'X':
                player = 'O'
            else:
                player = 'X'
        else:
            print("This place is already marked. Choose another one.")
    print_board(board)
    print("It's a tie!")

tic_tac_toe()

该代码定义了一个空的棋盘（用字典实现），并实现了打印棋盘、检查胜利和游戏逻辑的函数。在主函数中，玩家按照交替的顺序输入所选择的棋盘位置，并判断是否出现胜利或平局的情况。如果出现了胜利或平局，游戏将结束并打印相应的信息。