请用C++实现一个链表，把rating.json文件数据读入到链表中,文件里的每条记录包含如下字段信息,corp,from, to,score,comment, comments, time

好的，我会根据您的要求进行回答，不会透露您的任何要求。

以下是C++实现链表并读取rating.json文件数据的代码：

#include <iostream>
#include <fstream>
#include <string>
using namespace std;

// 定义链表结构体
struct Node {
    string corp;
    string from;
    string to;
    int score;
    string comment;
    int comments;
    string time;
    Node* next;
};

int main() {
    // 打开rating.json文件
    ifstream file("rating.json");
    if (!file) {
        cout << "文件打开失败！" << endl;
        return 0;
    }

    // 定义头结点和当前结点
    Node* head = new Node;
    Node* current = head;

    // 逐行读取文件数据并存入链表
    string line;
    while (getline(file, line)) {
        // 解析每行数据
        int index = line.find(',');
        string corp = line.substr(1, index - 2);
        line = line.substr(index + 1);

        index = line.find(',');
        string from = line.substr(1, index - 2);
        line = line.substr(index + 1);

        index = line.find(',');
        string to = line.substr(1, index - 2);
        line = line.substr(index + 1);

        index = line.find(',');
        int score = stoi(line.substr(1, index - 1));
        line = line.substr(index + 1);

        index = line.find(',');
        string comment = line.substr(1, index - 2);
        line = line.substr(index + 1);

        index = line.find(',');
        int comments = stoi(line.substr(1, index - 1));
        line = line.substr(index + 1);

        string time = line.substr(1, line.length() - 3);

        // 创建新结点并添加到链表中
        Node* node = new Node;
        node->corp = corp;
        node->from = from;
        node->to = to;
        node->score = score;
        node->comment = comment;
        node->comments = comments;
        node->time = time;
        node->next = nullptr;
        current->next = node;
        current = node;
    }

    // 关闭文件
    file.close();

    // 输出链表数据
    current = head->next;
    while (current != nullptr) {
        cout << current->corp << " "
             << current->from << " "
             << current->to << " "
             << current->score << " "
             << current->comment << " "
             << current->comments << " "
             << current->time << endl;
        current = current->next;
    }

    // 释放链表空间
    current = head;
    while (current != nullptr) {
        Node* next = current->next;
        delete current;
        current = next;
    }

    return 0;
}

注意，此代码仅供参考，具体实现可能需要根据实际情况进行调整。