python七段数码管绘制数字二代码

import turtle

# 7段数码管的线段坐标数据
segments = [
    [(0, 0), (0, 20)],  # a
    [(0, 20), (20, 20)],  # b
    [(20, 20), (20, 40)],  # c
    [(20, 40), (0, 40)],  # d
    [(0, 40), (0, 60)],  # e
    [(0, 60), (20, 60)],  # f
    [(20, 60), (20, 80)],  # g
]

def draw_segment(x, y, segment):
    # 在位置 (x, y) 画出一个线段
    turtle.penup()
    turtle.goto(x + segment[0][0], y + segment[0][1])
    turtle.pendown()
    for point in segment[1:]:
        turtle.goto(x + point[0], y + point[1])
        
def draw_digit(digit, x=0, y=0):
    # 绘制一个数字
    if digit in [2, 3, 4, 5, 6, 8, 9]:
        draw_segment(x, y, segments[0])  # a
    if digit in [0, 3, 4, 5, 6, 7, 8, 9]:
        draw_segment(x, y, segments[1])  # b
    if digit in [0, 1, 2, 3, 4, 7, 8, 9]:
        draw_segment(x, y, segments[2])  # c
    if digit in [0, 2, 3, 5, 6, 8, 9]:
        draw_segment(x, y, segments[3])  # d
    if digit in [0, 1, 3, 4, 5, 6, 7, 8, 9]:
        draw_segment(x, y, segments[4])  # e
    if digit in [0, 2, 6, 8]:
        draw_segment(x, y, segments[5])  # f
    if digit in [0, 1, 4, 7]:
        draw_segment(x, y, segments[6])  # g
        
def draw_number(number):
    # 绘制一个数字串
    for digit in number:
        draw_digit(int(digit))
        turtle.penup()
        turtle.forward(40)
        turtle.pendown()

# 测试代码
turtle.speed(0)
turtle.hideturtle()
turtle.penup()
turtle.goto(-200, 0)
turtle.pendown()
draw_number('2022')
turtle.done()

运行结果：