python七段数码管绘制a-f,0-9的代码用海龟绘图
时间: 2024-05-16 11:12:10 浏览: 114
当然可以,以下是一个简单的例子:
```python
import turtle
def draw_dash(length):
turtle.penup()
turtle.pendown()
turtle.forward(length)
turtle.penup()
def draw_segment(length, incline):
turtle.pendown()
angle = incline * turtle.heading()
turtle.setheading(angle)
turtle.forward(length)
turtle.penup()
angle = -incline * turtle.heading()
turtle.setheading(angle)
def draw_digit(digit, size=100):
turtle.setheading(90)
# 定义每个数字对应的数码段
segments = {0: [1,1,1,1,1,1,0],
1: [0,1,1,0,0,0,0],
2: [1,1,0,1,1,0,1],
3: [1,1,1,1,0,0,1],
4: [0,1,1,0,0,1,1],
5: [1,0,1,1,0,1,1],
6: [1,0,1,1,1,1,1],
7: [1,1,1,0,0,0,0],
8: [1,1,1,1,1,1,1],
9: [1,1,1,1,0,1,1],
'a': [1,1,1,0,1,1,1],
'b': [0,0,1,1,1,1,1],
'c': [1,0,0,1,1,1,0],
'd': [0,1,1,1,1,0,1],
'e': [1,0,0,1,1,1,1],
'f': [1,0,0,0,1,1,1]}
for i, segment in enumerate(segments[digit]):
if segment:
if i == 0:
draw_segment(size * 1.1, 2)
elif i == 1 or i == 2:
draw_segment(size, 1)
elif i == 3 or i == 4 or i == 5:
draw_segment(size, -1)
elif i == 6:
draw_segment(size * 1.1, -2)
else:
if i == 0:
draw_dash(size * 1.1)
elif i == 1 or i == 2 or i == 3 or i == 4 or i == 5:
draw_dash(size)
elif i == 6:
draw_dash(size * 1.1)
turtle.setheading(0)
# 测试绘制数字
turtle.penup()
turtle.goto(-200, 0)
draw_digit('a')
turtle.goto(-50, 0)
draw_digit('b')
turtle.goto(100, 0)
draw_digit('c')
turtle.goto(250, 0)
draw_digit('d')
turtle.done()
```
其中 `segments` 定义了每个数字对应的七段数码管的状态,`draw_segment` 和 `draw_dash` 分别用于绘制数码管和间隔线,`draw_digit` 则是根据 `segments` 中的状态来绘制数字。
在这个例子中,我们测试了绘制 a、b、c、d 四个字母/数字,你可以通过修改 `draw_digit` 中 `segments` 的值来绘制你所需要的数字或字母。
希望能对你有所帮助!
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