用C语言写一个贪吃蛇程序
时间: 2023-10-29 17:07:15 浏览: 137
用c语言编写贪吃蛇程序
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好的,以下是一个简单的贪吃蛇程序的C语言实现:
```
#include <stdio.h>
#include <conio.h>
#include <stdlib.h>
#include <windows.h>
int height = 20, width = 20;
int x, y, fruitX, fruitY, score, gameOver;
int tailX[100], tailY[100], nTail;
void Setup()
{
gameOver = 0;
x = width / 2;
y = height / 2;
fruitX = rand() % width;
fruitY = rand() % height;
score = 0;
}
void Draw()
{
system("cls");
for (int i = 0; i < width+2; i++)
printf("#");
printf("\n");
for (int i = 0; i < height; i++)
{
for (int j = 0; j < width; j++)
{
if (j == 0)
printf("#");
if (i == y && j == x)
printf("O");
else if (i == fruitY && j == fruitX)
printf("F");
else
{
int print = 0;
for (int k = 0; k < nTail; k++)
{
if (tailX[k] == j && tailY[k] == i)
{
printf("o");
print = 1;
}
}
if (!print)
printf(" ");
}
if (j == width - 1)
printf("#");
}
printf("\n");
}
for (int i = 0; i < width+2; i++)
printf("#");
printf("\n");
printf("Score: %d", score);
}
void Input()
{
if (_kbhit())
{
switch (_getch())
{
case 'a':
x--;
break;
case 'd':
x++;
break;
case 'w':
y--;
break;
case 's':
y++;
break;
case 'x':
gameOver = 1;
break;
}
}
}
void Logic()
{
int prevX = tailX[0];
int prevY = tailY[0];
int prev2X, prev2Y;
tailX[0] = x;
tailY[0] = y;
for (int i = 1; i < nTail; i++)
{
prev2X = tailX[i];
prev2Y = tailY[i];
tailX[i] = prevX;
tailY[i] = prevY;
prevX = prev2X;
prevY = prev2Y;
}
switch (_getch())
{
case 'a':
x--;
break;
case 'd':
x++;
break;
case 'w':
y--;
break;
case 's':
y++;
break;
case 'x':
gameOver = 1;
break;
}
if (x >= width)
x = 0;
else if (x < 0)
x = width - 1;
if (y >= height)
y = 0;
else if (y < 0)
y = height - 1;
for (int i = 0; i < nTail; i++)
if (tailX[i] == x && tailY[i] == y)
gameOver = 1;
if (x == fruitX && y == fruitY)
{
score += 10;
fruitX = rand() % width;
fruitY = rand() % height;
nTail++;
}
}
int main()
{
Setup();
while (!gameOver)
{
Draw();
Input();
Logic();
Sleep(20);
}
return 0;
}
```
这个程序可以在控制台中玩贪吃蛇游戏。如果您想打印带颜色的输出,请使用 `<windows.h>` 头文件中的 `SetConsoleTextAttribute()` 函数。
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