写一段完整的简易计算器C语言代码
时间: 2023-06-03 17:04:43 浏览: 128
好的,以下是一个简易计算器的C语言代码:
#include <stdio.h>
int main()
{
char operator;
int firstNumber, secondNumber, result;
printf("Enter an operator (+, -, *, /): ");
scanf("%c", &operator);
printf("Enter the first number: ");
scanf("%d", &firstNumber);
printf("Enter the second number: ");
scanf("%d", &secondNumber);
switch(operator)
{
case '+':
result = firstNumber + secondNumber;
break;
case '-':
result = firstNumber - secondNumber;
break
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简易计算器c语言代码
以下是一个简易的计算器的 C 语言代码:
```c
#include <stdio.h>
int main() {
char operator;
double num1, num2;
printf("请输入运算符 (+, -, *, /): ");
scanf("%c", &operator);
printf("请输入两个数字: ");
scanf("%lf %lf", &num1, &num2);
switch(operator) {
case '+':
printf("%.2lf + %.2lf = %.2lf", num1, num2, num1 + num2);
break;
case '-':
printf("%.2lf - %.2lf = %.2lf", num1, num2, num1 - num2);
break;
case '*':
printf("%.2lf * %.2lf = %.2lf", num1, num2, num1 * num2);
break;
case '/':
printf("%.2lf / %.2lf = %.2lf", num1, num2, num1 / num2);
break;
default:
printf("错误! 请输入正确的运算符");
}
return 0;
}
```
用C语言写一个简易计算器的代码
以下是一个简单的计算器代码,使用C语言编写:
#include <stdio.h>
int main() {
char operator;
double num1, num2;
printf("请输入运算符 (+, -, *, /): ");
scanf("%c", &operator);
printf("请输入两个数字: ");
scanf("%lf %lf", &num1, &num2);
switch(operator) {
case '+':
printf("%.1lf + %.1lf = %.1lf", num1, num2, num1 + num2);
break;
case '-':
printf("%.1lf - %.1lf = %.1lf", num1, num2, num1 - num2);
break;
case '*':
printf("%.1lf * %.1lf = %.1lf", num1, num2, num1 * num2);
break;
case '/':
printf("%.1lf / %.1lf = %.1lf", num1, num2, num1 / num2);
break;
default:
printf("错误! 请输入正确的运算符");
}
return 0;
}