Stream 将结果队伍中的字符串姓名作为Student对象的属性,创建Student对象,将集合中的元素都更改为Student类型
时间: 2024-06-11 16:11:10 浏览: 58
下面是一个示例代码:
```python
class Student:
def __init__(self, name):
self.name = name
students = []
results = ['Tom', 'Jerry', 'Alice', 'Bob']
students = list(map(lambda name: Student(name), results))
```
首先定义了一个`Student`类,具有一个`name`属性。然后定义了一个空列表`students`和一个包含字符串姓名的列表`results`。
使用`map`函数将`results`列表中的每个字符串姓名转换为`Student`对象,并将所有结果存储在`students`列表中。
现在`students`列表中包含了四个`Student`对象,可以使用`for`循环遍历列表并访问每个对象的`name`属性。
相关问题
设计一个模板类SET,集合中可以存放不同类型的对象;然后编写一个演示程序利用SET创建并使用整数的集合、字符串的集合以及学生的集合,学生类STUDENT是自己设计的类类型,包括对学生的学号、姓名、年龄、系别等信息的描述及必要的行为。(提示:集合中的元素不允许重复,且元素之间是无序的)SET类的原型可参考如下:template <class T>class SET {private:T elements[MAX_LEN];// 定义元素集合,来记录SET中的元素intN;// 定义元素的实际个数public:SET(); SET(T data[], int n);SET(const SET &obj);~SET();int hasElement(T one); //判断元素one是否在集合中void inputElement(T one); // 向集合中加入一个元素void delElement(T one);// 从集合中删除一个元素void showAllElements(); //显示集合中的所有元素// SET对象之间的运算:交、并、差,分别采用运算符重载实现SET operator+(const SET &obj);SET operator*(const SET &obj);SET operator-(const SET &obj);SET operator=(const SET &obj);};STUDENT类的原型可参考如下:class STUDENT{private:long id;char name[MAX_LEN];char sex;int age;public:STUDENT();STUDENT(const STUDENT& obj);STUDENT(long idd, char namee[], char sexx, int agee);~STUDENT();int operator==(const STUDENT& obj);STUDENT operator=(const STUDENT& obj);// 定义友元函数friend ostream& operator<<(ostream& stream, const STUDENT& obj);};题目说明:1)SET中的数据可以使用固定长度的数组存储,也可以使用动态数组存储,也可
以其他方式存储;
2)在演示程序中,需要创建整数、字符串和学生的集合,并进行交、并、差等运算;
3)在STUDENT类中,需要重载==运算符和=运算符,并定义友元函数ostream& operator<<(ostream& stream, const STUDENT& obj),用于输出学生信息。
下面是一个可能的实现:
```cpp
#include <iostream>
#include <cstring>
using namespace std;
const int MAX_LEN = 100;
template <class T>
class SET {
private:
T elements[MAX_LEN];
int N;
public:
SET() {
N = 0;
}
SET(T data[], int n) {
N = 0;
for (int i = 0; i < n; i++) {
inputElement(data[i]);
}
}
SET(const SET &obj) {
N = obj.N;
for (int i = 0; i < N; i++) {
elements[i] = obj.elements[i];
}
}
~SET() {}
int hasElement(T one) {
for (int i = 0; i < N; i++) {
if (elements[i] == one) {
return i;
}
}
return -1;
}
void inputElement(T one) {
if (hasElement(one) == -1) {
elements[N++] = one;
}
}
void delElement(T one) {
int index = hasElement(one);
if (index != -1) {
for (int i = index; i < N - 1; i++) {
elements[i] = elements[i + 1];
}
N--;
}
}
void showAllElements() {
for (int i = 0; i < N; i++) {
cout << elements[i] << " ";
}
cout << endl;
}
SET operator+(const SET &obj) {
SET result;
for (int i = 0; i < N; i++) {
result.inputElement(elements[i]);
}
for (int i = 0; i < obj.N; i++) {
result.inputElement(obj.elements[i]);
}
return result;
}
SET operator*(const SET &obj) {
SET result;
for (int i = 0; i < N; i++) {
if (obj.hasElement(elements[i]) != -1) {
result.inputElement(elements[i]);
}
}
return result;
}
SET operator-(const SET &obj) {
SET result;
for (int i = 0; i < N; i++) {
if (obj.hasElement(elements[i]) == -1) {
result.inputElement(elements[i]);
}
}
return result;
}
SET operator=(const SET &obj) {
N = obj.N;
for (int i = 0; i < N; i++) {
elements[i] = obj.elements[i];
}
return *this;
}
};
class STUDENT {
private:
long id;
char name[MAX_LEN];
char sex;
int age;
public:
STUDENT() {}
STUDENT(const STUDENT& obj) {
id = obj.id;
strcpy(name, obj.name);
sex = obj.sex;
age = obj.age;
}
STUDENT(long idd, char namee[], char sexx, int agee) {
id = idd;
strcpy(name, namee);
sex = sexx;
age = agee;
}
~STUDENT() {}
int operator==(const STUDENT& obj) {
return (id == obj.id && strcmp(name, obj.name) == 0 && sex == obj.sex && age == obj.age);
}
STUDENT operator=(const STUDENT& obj) {
id = obj.id;
strcpy(name, obj.name);
sex = obj.sex;
age = obj.age;
return *this;
}
friend ostream& operator<<(ostream& stream, const STUDENT& obj) {
stream << obj.id << " " << obj.name << " " << obj.sex << " " << obj.age;
return stream;
}
};
int main() {
SET<int> intSet1, intSet2;
intSet1.inputElement(1);
intSet1.inputElement(2);
intSet1.inputElement(3);
intSet2.inputElement(2);
intSet2.inputElement(3);
intSet2.inputElement(4);
SET<int> intSet3 = intSet1 + intSet2;
SET<int> intSet4 = intSet1 * intSet2;
SET<int> intSet5 = intSet1 - intSet2;
cout << "Int Set 1: ";
intSet1.showAllElements();
cout << "Int Set 2: ";
intSet2.showAllElements();
cout << "Int Set 1 + Int Set 2: ";
intSet3.showAllElements();
cout << "Int Set 1 * Int Set 2: ";
intSet4.showAllElements();
cout << "Int Set 1 - Int Set 2: ";
intSet5.showAllElements();
SET<string> stringSet1, stringSet2;
stringSet1.inputElement("hello");
stringSet1.inputElement("world");
stringSet2.inputElement("world");
stringSet2.inputElement("!");
SET<string> stringSet3 = stringSet1 + stringSet2;
SET<string> stringSet4 = stringSet1 * stringSet2;
SET<string> stringSet5 = stringSet1 - stringSet2;
cout << "String Set 1: ";
stringSet1.showAllElements();
cout << "String Set 2: ";
stringSet2.showAllElements();
cout << "String Set 1 + String Set 2: ";
stringSet3.showAllElements();
cout << "String Set 1 * String Set 2: ";
stringSet4.showAllElements();
cout << "String Set 1 - String Set 2: ";
stringSet5.showAllElements();
STUDENT student1(1, "Alice", 'F', 20), student2(2, "Bob", 'M', 21), student3(3, "Charlie", 'M', 22);
SET<STUDENT> studentSet1, studentSet2;
studentSet1.inputElement(student1);
studentSet1.inputElement(student2);
studentSet2.inputElement(student2);
studentSet2.inputElement(student3);
SET<STUDENT> studentSet3 = studentSet1 + studentSet2;
SET<STUDENT> studentSet4 = studentSet1 * studentSet2;
SET<STUDENT> studentSet5 = studentSet1 - studentSet2;
cout << "Student Set 1: ";
studentSet1.showAllElements();
cout << "Student Set 2: ";
studentSet2.showAllElements();
cout << "Student Set 1 + Student Set 2: ";
studentSet3.showAllElements();
cout << "Student Set 1 * Student Set 2: ";
studentSet4.showAllElements();
cout << "Student Set 1 - Student Set 2: ";
studentSet5.showAllElements();
return 0;
}
```
如何从student类的list对象的stream流中获取所有对象并整体转化为字符串
要将整个`Student`对象列表转换为一个字符串,您可以使用流的`map()`方法将每个`Student`对象转换为字符串表示,然后使用`collect()`方法将所有字符串连接起来。以下是一个示例代码:
```java
import java.util.ArrayList;
import java.util.List;
import java.util.stream.Collectors;
public class Main {
public static void main(String[] args) {
List<Student> students = new ArrayList<>();
students.add(new Student("John", 20));
students.add(new Student("Alice", 22));
students.add(new Student("Bob", 19));
String studentsString = students.stream()
.map(Student::toString) // 将每个Student对象转为字符串
.collect(Collectors.joining(", ")); // 将所有字符串连接起来
System.out.println(studentsString);
}
}
class Student {
private String name;
private int age;
public Student(String name, int age) {
this.name = name;
this.age = age;
}
@Override
public String toString() {
return "Name: " + name + ", Age: " + age;
}
}
```
在这个示例中,我们首先创建了一个包含三个`Student`对象的`List`。然后,我们使用流的`map()`方法将每个`Student`对象转换为字符串表示,这里使用了对象的`toString()`方法。最后,我们使用`collect()`方法和`Collectors.joining()`将所有字符串连接起来,使用逗号和空格作为分隔符。最终,将整个字符串打印出来。
请注意,这里的`toString()`方法是根据`Student`类的实现来进行的,您可以根据实际情况修改`Student`类和转换逻辑。
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