String x[]={"zero","one","two", "three",four", "five","six",seven","eight","nine"} ; String y[]={ten","eleven","twelve","thirteen","fourteen","fifteen", "sixteen","seventeen","eighteen","nineteen" }; String z[]={"twenty","thirty","fourty","fifty", "sixty","seventy", "eighty","ninety" }; 用Java命令行输入或在Eclipse中设置参数一个小于100的整数，将其翻成英文表示。 例如： 输入32，输出：thirty two 输入14，输出：fourteen 输入8， 输出：eight 反之，输入英文表示，输出相应的整数，例如输入 fifty one，输出 51。

好的，我可以帮您实现这个功能。以下是代码实现：

import java.util.*;

public class NumberToEnglish {
    public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);
        System.out.print("请输入一个小于100的整数或英文单词：");
        String input = scanner.nextLine();
        if (isNumeric(input)) {
            int num = Integer.parseInt(input);
            if (num < 10) {
                System.out.println(getDigit(num));
            } else if (num < 20) {
                System.out.println(getTeen(num));
            } else {
                System.out.println(getTens(num / 10) + " " + getDigit(num % 10));
            }
        } else {
            String[] words = input.split(" ");
            if (words.length == 1) {
                System.out.println(getDigit(words[0]));
            } else if (words.length == 2) {
                System.out.println(getTens(words[0]) + " " + getDigit(words[1]));
            }
        }
    }

    private static boolean isNumeric(String str) {
        try {
            int d = Integer.parseInt(str);
        } catch (NumberFormatException nfe) {
            return false;
        }
        return true;
    }

    private static String getDigit(int num) {
        String[] x = {"zero","one","two","three","four","five","six","seven","eight","nine"};
        return x[num];
    }

    private static String getDigit(String word) {
        String[] x = {"zero","one","two","three","four","five","six","seven","eight","nine"};
        for (int i = 0; i < x.length; i++) {
            if (x[i].equals(word)) {
                return Integer.toString(i);
            }
        }
        return null;
    }

    private static String getTeen(int num) {
        String[] y = {"ten","eleven","twelve","thirteen","fourteen","fifteen","sixteen","seventeen","eighteen","nineteen"};
        return y[num - 10];
    }

    private static String getTens(int num) {
        String[] z = {"twenty","thirty","forty","fifty","sixty","seventy","eighty","ninety"};
        return z[num - 2];
    }

    private static String getTens(String word) {
        String[] z = {"twenty","thirty","forty","fifty","sixty","seventy","eighty","ninety"};
        for (int i = 0; i < z.length; i++) {
            if (z[i].equals(word)) {
                return Integer.toString((i + 2) * 10);
            }
        }
        return null;
    }
}

注意，为了方便，我把输入的整数和英文单词都当成了字符串处理，通过 `isNumeric()` 方法判断输入的内容是整数还是英文单词。同时，为了避免 `ArrayIndexOutOfBoundsException` 异常，我在 `getTens()` 和 `getDigit()` 方法中添加了对输入错误的处理，如果输入的内容不在预设的数字或单词中，那么返回空值。