用C语言写一个短作业优先调度算法程序

好的，我可以帮您用C语言编写一个短作业优先调度算法程序。以下是代码：

#include<stdio.h>

struct process{
    char pid[5];
    int at, bt, ct, tat, wt;
    int completed;
    float ntt;
}p[10], temp;

int n;

void sortByArrival(){
    int i, j;
    for(i=0; i<n-1; i++){
        for(j=i+1; j<n; j++){
            if(p[i].at > p[j].at){
                temp = p[i];
                p[i] = p[j];
                p[j] = temp;
            }
        }
    }
}

void main(){
    int i, j, t, sum_bt=0;
    char c;
    float avgwt=0, avgtat=0, avgntt=0;

    printf("Enter the no of processes: ");
    scanf("%d", &n);

    for(i=0, c='A'; i<n; i++, c++){
        p[i].pid[0] = c;
        printf("\nEnter the arrival time and burst time of process %c: ", p[i].pid[0]);
        scanf("%d%d", &p[i].at, &p[i].bt);
        p[i].completed = 0;

        sum_bt += p[i].bt;
    }

    sortByArrival();
    printf("\nProcess\tArrival Time\tBurst Time\tCompletion Time\tTurn-Around Time\tWaiting Time\t Normalized TAT");

    for(t = p[0].at; t < sum_bt;){
        float hrr = -9999;
        for(i=0; i<n; i++){
            if(p[i].at <= t && !p[i].completed){
                float temp = (p[i].bt + (t - p[i].at)) / p[i].bt;
                if(hrr < temp){
                    hrr = temp;
                    j = i;
                }
            }
        }

        p[j].ct = t + p[j].bt;
        p[j].tat = p[j].ct - p[j].at;
        p[j].wt = p[j].tat - p[j].bt;
        p[j].ntt = ((float)p[j].tat / p[j].bt);

        avgwt += p[j].wt;
        avgtat += p[j].tat;
        avgntt += p[j].ntt;

        p[j].completed = 1;
        t = p[j].ct;

        printf("\n%c\t\t%d\t\t%d\t\t%d\t\t\t%d\t\t\t%d\t\t\t%f", p[j].pid[0], p[j].at, p[j].bt, p[j].ct, p[j].tat, p[j].wt, p[j].ntt);
    }

    printf("\nAverage waiting time: %f\n", avgwt/n);
    printf("Average turn-around time: %f\n", avgtat/n);
    printf("Average normalized TAT: %f\n", avgntt/n);
}

这是一个简单的短作业优先调度算法程序，它会根据进程的到达时间和运行时间，按照优先级将进程调度到CPU中。程序会输出每个进程的完成时间、周转时间、等待时间和标准化周转时间。最后，程序会计算平均等待时间、平均周转时间和平均标准化周转时间，并将它们输出到屏幕上。