使用Verilog设计两组交通信号灯
时间: 2024-01-19 15:51:30 浏览: 71
以下是使用 Verilog 设计两组交通信号灯的代码示例:
```verilog
module traffic_light (
input clk, // 时钟信号
output reg red1, yellow1, green1, red2, yellow2, green2 // 输出信号
);
parameter red_time = 20000000; // 红灯持续时间
parameter green_time = 40000000; // 绿灯持续时间
parameter yellow_time = 3000000; // 黄灯持续时间
reg [23:0] counter1 = 0; // 计数器1
reg [23:0] counter2 = 0; // 计数器2
reg [1:0] state1 = 0; // 状态1
reg [1:0] state2 = 0; // 状态2
always @(posedge clk) begin
// 状态1的状态转移
case (state1)
0: begin // 红灯
counter1 <= counter1 + 1;
if (counter1 >= red_time) begin
counter1 <= 0;
state1 <= 1;
end
red1 <= 1;
yellow1 <= 0;
green1 <= 0;
end
1: begin // 绿灯
counter1 <= counter1 + 1;
if (counter1 >= green_time) begin
counter1 <= 0;
state1 <= 2;
end
red1 <= 0;
yellow1 <= 0;
green1 <= 1;
end
2: begin // 黄灯
counter1 <= counter1 + 1;
if (counter1 >= yellow_time) begin
counter1 <= 0;
state1 <= 0;
end
red1 <= 0;
yellow1 <= 1;
green1 <= 0;
end
endcase
// 状态2的状态转移
case (state2)
0: begin // 红灯
counter2 <= counter2 + 1;
if (counter2 >= red_time) begin
counter2 <= 0;
state2 <= 1;
end
red2 <= 1;
yellow2 <= 0;
green2 <= 0;
end
1: begin // 绿灯
counter2 <= counter2 + 1;
if (counter2 >= green_time) begin
counter2 <= 0;
state2 <= 2;
end
red2 <= 0;
yellow2 <= 0;
green2 <= 1;
end
2: begin // 黄灯
counter2 <= counter2 + 1;
if (counter2 >= yellow_time) begin
counter2 <= 0;
state2 <= 0;
end
red2 <= 0;
yellow2 <= 1;
green2 <= 0;
end
endcase
end
endmodule
```
此代码使用有限状态机实现了两组交通信号灯的控制。在状态 `0` 中,红灯亮,其它灯灭;在状态 `1` 中,绿灯亮,其它灯灭;在状态 `2` 中,黄灯亮,其它灯灭。每个状态持续一定的时间后,状态会转移到下一个状态。在此代码中,红灯持续 20 秒,绿灯持续 40 秒,黄灯持续 3 秒。
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