用c/c++ 编程实现一个推箱子

推箱子是一个经典的游戏，可以用C/C++编程语言来实现。下面是一个简单的推箱子的实现代码。

#include <iostream>
#include <vector>
using namespace std;

struct Point {
    int x, y;
    Point(int x, int y) : x(x), y(y) {}
};

class BoxGame {
private:
    int m, n;
    vector<vector<char>> board;
    Point player;
    vector<Point> boxes;
public:
    BoxGame(int m, int n, vector<vector<char>>& board) : m(m), n(n), board(board) {
        for (int i = 0; i < m; i++) {
            for (int j = 0; j < n; j++) {
                if (board[i][j] == 'P') {
                    player = Point(i, j);
                } else if (board[i][j] == 'B') {
                    boxes.push_back(Point(i, j));
                }
            }
        }
    }

    void move(char direction) {
        int dx = 0, dy = 0;
        if (direction == 'U') {
            dx = -1;
        } else if (direction == 'D') {
            dx = 1;
        } else if (direction == 'L') {
            dy = -1;
        } else if (direction == 'R') {
            dy = 1;
        }

        Point new_player(player.x + dx, player.y + dy);
        if (new_player.x < 0 || new_player.x >= m || new_player.y < 0 || new_player.y >= n || board[new_player.x][new_player.y] == '#') {
            return;
        }

        bool can_move = true;
        for (int i = 0; i < boxes.size(); i++) {
            if (boxes[i].x == new_player.x && boxes[i].y == new_player.y) {
                Point new_box(boxes[i].x + dx, boxes[i].y + dy);
                if (new_box.x < 0 || new_box.x >= m || new_box.y < 0 || new_box.y >= n || board[new_box.x][new_box.y] == '#' || (new_box.x == player.x && new_box.y == player.y)) {
                    can_move = false;
                    break;
                }
                boxes[i] = new_box;
                break;
            }
        }

        if (can_move) {
            player = new_player;
        }

        print_board();
        if (is_win()) {
            cout << "You win!" << endl;
        }
    }

    bool is_win() {
        for (int i = 0; i < boxes.size(); i++) {
            if (board[boxes[i].x][boxes[i].y] != 'G') {
                return false;
            }
        }
        return true;
    }

    void print_board() {
        for (int i = 0; i < m; i++) {
            for (int j = 0; j < n; j++) {
                if (player.x == i && player.y == j) {
                    cout << 'P';
                } else {
                    bool is_box = false;
                    for (int k = 0; k < boxes.size(); k++) {
                        if (boxes[k].x == i && boxes[k].y == j) {
                            cout << 'B';
                            is_box = true;
                            break;
                        }
                    }
                    if (!is_box) {
                        cout << board[i][j];
                    }
                }
            }
            cout << endl;
        }
        cout << endl;
    }
};

int main() {
    vector<vector<char>> board{
        {'#', '#', '#', '#', '#', '#', '#', '#', '#', '#'},
        {'#', 'P', '#', '#', '#', ' ', ' ', ' ', ' ', '#'},
        {'#', ' ', '#', '#', '#', ' ', ' ', ' ', ' ', '#'},
        {'#', ' ', ' ', ' ', 'B', ' ', ' ', ' ', ' ', '#'},
        {'#', ' ', ' ', ' ', '#', ' ', ' ', ' ', ' ', '#'},
        {'#', ' ', ' ', ' ', ' ', ' ', ' ', ' ', ' ', '#'},
        {'#', ' ', ' ', ' ', ' ', ' ', ' ', ' ', ' ', '#'},
        {'#', ' ', ' ', ' ', ' ', ' ', ' ', ' ', ' ', '#'},
        {'#', ' ', ' ', ' ', ' ', ' ', ' ', ' ', ' ', '#'},
        {'#', '#', '#', '#', '#', '#', '#', '#', '#', '#'}
    };

    BoxGame game(10, 10, board);
    game.print_board();

    while (true) {
        char direction;
        cout << "Enter move (U/D/L/R): ";
        cin >> direction;
        game.move(direction);
    }

    return 0;
}

这个实现采用了面向对象的思想，将游戏板面、玩家、箱子等都封装到了一个BoxGame类中。move方法用于移动玩家，is_win方法用于判断是否胜利，print_board方法用于打印游戏板面。在主函数中，先构造一个游戏对象，然后循环读入玩家的移动指令，并调用move方法移动玩家。