#include<stdio.h> int main() { int n; int a[100]; int i = 1; printf("please input n"); scanf_s("%d", &n); while (n--) { printf("input the number") scanf_s("%d",&a[i]); i++; } n = i - 1; i = 1; printf("please input the number to find"); int goal; scanf_s("%d", &goal); for (i = 1; i <= n; i++) { if (goal == a[i]) { printf("%d", found it : i); i = n + 2; } } if (i = n + 1) printf("can't find it") return 0; }把这个c++改成python语言

当然可以，这是一段C++代码：

#include<stdio.h> 
int main() { 
    int n; 
    int a[100]; 
    int i = 1; 
    printf("please input n"); 
    scanf_s("%d", &n); 
    while (n--) { 
        printf("input the number"); 
        scanf_s("%d",&a[i]); 
        i++; 
    } 
    n = i - 1; 
    i = 1; 
    printf("please input the number to find"); 
    int goal; 
    scanf_s("%d", &goal); 
    for (i = 1; i <= n; i++) { 
        if (goal == a[i]) { 
            printf("%d", found it : i); 
            i = n + 2; 
        } 
    } 
    if (i = n + 1) 
        printf("can't find it"); 
    return 0; 
}

这是对应的Python代码：

n = int(input("please input n: "))
a = []
for i in range(n):
    a.append(int(input("input the number: ")))
goal = int(input("please input the number to find: "))
for i in range(n):
    if goal == a[i]:
        print("found it: ", i+1)
        break
else:
    print("can't find it")