编写程序实现两个整数集合的基本运算： S1+S2 集合并运算 S1-S2 集合差运算 S1*S2 集合交运算 要求：输入整数集合{2 4 1 3 5}和{2 5 10}，输出前者元素个数以及它们进行集合并、差、交运算后的结果。c++实现

以下是C++实现的代码：

#include <iostream>
#include <set>
#include <algorithm>

using namespace std;

int main() {
    set<int> S1 = {2, 4, 1, 3, 5};
    set<int> S2 = {2, 5, 10};

    // 集合并运算
    set<int> S_union;
    set_union(S1.begin(), S1.end(), S2.begin(), S2.end(), inserter(S_union, S_union.begin()));
    cout << "S1+S2: ";
    for (auto it = S_union.begin(); it != S_union.end(); ++it) {
        cout << *it << " ";
    }
    cout << endl;

    // 集合差运算
    set<int> S_diff;
    set_difference(S1.begin(), S1.end(), S2.begin(), S2.end(), inserter(S_diff, S_diff.begin()));
    cout << "S1-S2: ";
    for (auto it = S_diff.begin(); it != S_diff.end(); ++it) {
        cout << *it << " ";
    }
    cout << endl;

    // 集合交运算
    set<int> S_intersection;
    set_intersection(S1.begin(), S1.end(), S2.begin(), S2.end(), inserter(S_intersection, S_intersection.begin()));
    cout << "S1*S2: ";
    for (auto it = S_intersection.begin(); it != S_intersection.end(); ++it) {
        cout << *it << " ";
    }
    cout << endl;

    // 元素个数
    cout << "S1元素个数：" << S1.size() << endl;

    return 0;
}

输出结果为：

S1+S2: 1 2 3 4 5 10 
S1-S2: 1 3 4 
S1*S2: 2 5 
S1元素个数：5