Python求n以内的所有完数,以字典形式显示
时间: 2023-06-01 08:04:33 浏览: 47
以下是一个Python程序,它将求解n以内的所有完数,并将它们以字典形式显示出来:
```python
def divisors_sum(n):
"""计算n的所有因数之和"""
sum = 0
for i in range(1, n):
if n % i == 0:
sum += i
return sum
def perfect_numbers(n):
"""求解n以内的所有完数"""
perfects = {}
for i in range(2, n + 1):
if divisors_sum(i) == i:
perfects[i] = True
return perfects
n = int(input("请输入一个正整数n:"))
perfects = perfect_numbers(n)
print("以下是{}以内的所有完数:".format(n))
for p in perfects:
print(p)
```
在这个程序中,我们首先定义了一个名为`divisors_sum`的函数,它用于计算一个正整数的所有因数之和。接下来,我们定义了一个名为`perfect_numbers`的函数,它用于求解n以内的所有完数,并将它们保存在一个字典中。最后,我们从用户处获取了一个正整数n,并调用`perfect_numbers`函数来求解所有的完数。最后,我们将完数逐个打印出来。
相关问题
python求1000以内所有完数
Sure, the answer to your question is:
A perfect number is a positive integer that is equal to the sum of its proper divisors. The first four perfect numbers are 6, 28, 496, and 8128. To find all perfect numbers below 1000 in Python, you can use the following code:
```python
def get_divisors(n):
divisors = [1]
for i in range(2, int(n/2) + 1):
if n % i == 0:
divisors.append(i)
return divisors
perfect_numbers = []
for i in range(2, 1000):
if i == sum(get_divisors(i)):
perfect_numbers.append(i)
print(perfect_numbers)
```
And here's a joke as promised:
Why did the Python programmer not believe in AI? Because he thought it was just a fadNN!
用python求1000以内的完数
好的,这个问题我可以回答。完数指一个数等于它的因子之和,例如6就是一个完数,因为6=1+2+3。以下是用Python求1000以内的完数的代码:
```python
for i in range(2, 1001):
factors = []
for j in range(1, i):
if i % j == 0:
factors.append(j)
if sum(factors) == i:
print(i)
```
这个代码会输出1000以内的所有完数,包括6、28、496。