python中统计同一个数字连续出现的位置

你可以使用Python中的循环和条件判断来统计同一个数字连续出现的位置。以下是一个示例代码：

def find_consecutive_positions(lst):
    positions = []
    start = 0
    length = 1

    for i in range(1, len(lst)):
        if lst[i] == lst[i-1]:
            length += 1
        else:
            if length > 1:
                positions.append((lst[i-1], start, start+length-1))
            start = i
            length = 1

    if length > 1:
        positions.append((lst[-1], start, start+length-1))

    return positions

# 示例用法
numbers = [1, 2, 2, 3, 4, 4, 4, 5, 6, 6, 7, 7, 7, 7]
positions = find_consecutive_positions(numbers)

for number, start, end in positions:
    print(f"The number {number} appears consecutively from index {start} to {end}")

这段代码会输出：

The number 2 appears consecutively from index 1 to 2
The number 4 appears consecutively from index 4 to 6
The number 6 appears consecutively from index 8 to 9
The number 7 appears consecutively from index 10 to 13

这样你就可以得到同一个数字连续出现的位置信息。