jpa的findAll如何使用Example拼接where in
时间: 2024-05-06 20:21:17 浏览: 7
语句?
Example的构造函数可以传入一个ExampleMatcher对象,该对象定义用于匹配的规则。例如,要查询的实体类为User,以下是使用Example拼接where in语句的示例代码:
```
List<String> names = Arrays.asList("Tom", "Jerry", "Lucy");
ExampleMatcher matcher = ExampleMatcher.matching()
.withMatcher("name", ExampleMatcher.GenericPropertyMatchers.in());
Example<User> example = Example.of(new User(), matcher);
List<User> userList = userRepository.findAll(example);
```
以上代码使用ExampleMatcher的withMatcher方法指定了User实体的name字段匹配规则为in。然后创建了一个User实体对象作为查询条件,该对象的name属性为null,并将该对象包装为Example对象。最后调用userRepository的findAll方法查询并返回结果列表。
相关问题
jpa中使用example拼接in条件
好的,关于使用 JPA 中的 Example 来拼接 in 条件,可以使用 Example 对象的 createCriteria 方法来创建 Criteria 对象,然后使用 Criteria 对象的 in 方法来添加 in 条件。具体的实现可以参考 JPA 的文档或者使用一些开源框架来简化代码。如果您有其他问题,欢迎继续向我提问。
jpa中使用example拼接in条件的 代码示例
Sure, I'd be happy to help you with that! Here's an example of how you can use `Example` in JPA to create an IN condition:
```
// Create a list of values to use in the IN condition
List<String> names = Arrays.asList("John", "Jane", "Bob");
// Create a new Example object for the entity you want to query
Example<Person> example = Example.of(new Person(), ExampleMatcher.matchingAll()
// Use the 'in' method of the ExampleMatcher to specify the property to match on ('name')
.withMatcher("name", ExampleMatcher.GenericPropertyMatcher.of(ExampleMatcher.StringMatcher.IN)));
// Use the Example object as part of your JPA query
List<Person> results = repository.findAll(example);
```
In this example, we're creating an `Example` object for a `Person` entity, and using the `matchingAll()` method to specify that we want to match all properties of the entity. We then use the `withMatcher()` method to specify that we want to match on the `name` property, and use the `IN` matcher to specify that we want to match on a list of values.
Finally, we use the `Example` object as part of a JPA query using the `findAll()` method on our repository.
I hope this helps! Let me know if you have any other questions.