补充#include <stdio.h> #include <stdlib.h> #include <math.h> double square(double x) { return x*x; } double cube(double x) { return x*x*x; } /*你编写的积分函数嵌入在这里*/ int main() { /*求平方函数在区间[0,2]上的定积分*/ printf("square=%f\n",integration(square,0,2,10000)); /*求立方函数在区间[0,2]上的定积分*/ printf("cube=%f\n",integration(cube,0,2,10000)); /*求正弦函数在区间[0,2]上的定积分*/ printf("sin=%f\n",integration(sin,0,2,10000)); return 0; }
时间: 2024-02-15 08:02:06 浏览: 167
好的,下面是完整的代码,其中包括integration函数的实现:
```c
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
double square(double x) {
return x * x;
}
double cube(double x) {
return x * x * x;
}
double integration(double (*f)(double), double a, double b, int n) {
double dx = (b - a) / n;
double sum = 0.0;
for (int i = 0; i < n; i++) {
double x = a + i * dx;
sum += f(x) * dx;
}
return sum;
}
int main() {
printf("square=%f\n", integration(square, 0, 2, 10000));
printf("cube=%f\n", integration(cube, 0, 2, 10000));
printf("sin=%f\n", integration(sin, 0, 2, 10000));
return 0;
}
```
在这个程序中,square和cube函数分别返回参数x的平方和立方。integration函数接受一个指向函数的指针f,表示待积分的函数,在定义的区间[a,b]上将区间分成n个小区间,并计算每个小区间的面积贡献,最后返回总面积。在main函数中,我们分别计算了三个不同函数在指定区间上的定积分,并通过printf函数输出结果。
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