Python模拟电梯七段数码管绘制显示编程 利用turtle函数 假设你要乘坐电梯，假设只有一部电梯，其显示面板上有七段数码管显味 电梯当前所在楼层。假设你的学号为M， 且第(M%7+1）段数码管坏了（一直是亮的），问题：你现在在1楼，电梯停在 (M与N均小于等于9）请模拟你按了电梯后，到你到达 M楼，你要去N楼， N楼这个过程中，显示面饭上七段数码管的显示过程（假设这期间没有其他人 按电梯)

好的，我理解了你的问题。以下是 Python 代码实现：

import turtle
import time

# 设置数码管的位置和大小
def drawLine(draw, x1, y1, x2, y2):
    turtle.penup()
    turtle.goto(x1, y1)
    turtle.pendown()
    turtle.goto(x2, y2)
    turtle.penup()

# 绘制数字 0
def drawZero():
    drawLine(True, -30, 60, -30, 10)
    drawLine(True, -30, 10, 30, 10)
    drawLine(True, 30, 10, 30, 60)
    drawLine(True, 30, 60, -30, 60)

# 绘制数字 1
def drawOne():
    drawLine(True, 0, 60, 0, 10)

# 绘制数字 2
def drawTwo():
    drawLine(True, -30, 60, 30, 60)
    drawLine(True, 30, 60, 30, 35)
    drawLine(True, 30, 35, -30, 35)
    drawLine(True, -30, 35, -30, 10)
    drawLine(True, -30, 10, 30, 10)

# 绘制数字 3
def drawThree():
    drawLine(True, -30, 60, 30, 60)
    drawLine(True, 30, 60, 30, 35)
    drawLine(True, 30, 35, -30, 35)
    drawLine(True, 30, 35, 30, 10)
    drawLine(True, -30, 10, 30, 10)

# 绘制数字 4
def drawFour():
    drawLine(True, -30, 60, -30, 35)
    drawLine(True, -30, 35, 30, 35)
    drawLine(True, 30, 60, 30, 35)
    drawLine(True, 30, 35, 30, 10)

# 绘制数字 5
def drawFive():
    drawLine(True, 30, 60, -30, 60)
    drawLine(True, -30, 60, -30, 35)
    drawLine(True, -30, 35, 30, 35)
    drawLine(True, 30, 35, 30, 10)
    drawLine(True, 30, 10, -30, 10)

# 绘制数字 6
def drawSix():
    drawLine(True, 30, 60, -30, 60)
    drawLine(True, -30, 60, -30, 10)
    drawLine(True, -30, 10, 30, 10)
    drawLine(True, 30, 10, 30, 35)
    drawLine(True, 30, 35, -30, 35)

# 绘制数字 7
def drawSeven():
    drawLine(True, -30, 60, 30, 60)
    drawLine(True, 30, 60, 0, 10)

# 绘制数字 8
def drawEight():
    drawLine(True, -30, 60, -30, 10)
    drawLine(True, -30, 10, 30, 10)
    drawLine(True, 30, 10, 30, 60)
    drawLine(True, 30, 60, -30, 60)
    drawLine(True, -30, 35, 30, 35)

# 绘制数字 9
def drawNine():
    drawLine(True, 30, 60, -30, 60)
    drawLine(True, -30, 60, -30, 35)
    drawLine(True, -30, 35, 30, 35)
    drawLine(True, 30, 35, 30, 60)
    drawLine(True, 30, 35, -30, 10)

# 绘制数字
def drawDigit(digit):
    if digit == 0:
        drawZero()
    elif digit == 1:
        drawOne()
    elif digit == 2:
        drawTwo()
    elif digit == 3:
        drawThree()
    elif digit == 4:
        drawFour()
    elif digit == 5:
        drawFive()
    elif digit == 6:
        drawSix()
    elif digit == 7:
        drawSeven()
    elif digit == 8:
        drawEight()
    elif digit == 9:
        drawNine()

# 绘制当前楼层
def drawFloor(floor):
    turtle.clear()
    turtle.pensize(5)
    turtle.pencolor("blue")
    drawDigit(floor)

# 电梯运行到指定楼层
def elevatorMove(curFloor, targetFloor):
    if curFloor == targetFloor:
        return
    elif curFloor < targetFloor:
        for i in range(curFloor, targetFloor):
            drawFloor(i)
            time.sleep(0.5)
    else:
        for i in range(curFloor, targetFloor, -1):
            drawFloor(i)
            time.sleep(0.5)

# 模拟按电梯
def pressElevator(M, N):
    turtle.speed(0)
    turtle.hideturtle()
    # 坏掉的数码管
    badDigit = (M % 7) + 1
    # 当前楼层
    curFloor = 1
    # 前一次绘制的数字
    prevDigit = -1
    while curFloor != M:
        drawFloor(curFloor)
        curFloor += 1
        time.sleep(0.5)
    drawFloor(M)
    time.sleep(1)
    while curFloor != N:
        drawFloor(curFloor)
        digit = curFloor % 10
        if digit == badDigit:
            continue
        if prevDigit != digit:
            drawDigit(digit)
            prevDigit = digit
        curFloor += 1
        time.sleep(0.5)
    drawFloor(N)
    time.sleep(1)
    turtle.clear()

# 测试
pressElevator(4, 8)

在这个程序中，我们使用 Turtle 模块来绘制数码管，每次绘制一个数字时，都会清除之前的数字。我们模拟了按电梯的过程，从当前楼层到目标楼层，期间不显示坏掉的数码管。你可以替换 `pressElevator(4, 8)` 中的参数来测试其他的楼层。