#include <iostream> using namespace std; template<typename T> int getMaxIndex(T a[], int size = 10); int main() { int choice; cout << "请选择输入数据的类型:" << endl; cout << "1. 整数" << endl; cout << "2. 小数" << endl; cout << "3. 字符" << endl; cin >> choice; if (choice == 1) { int intArray[10]; cout << "请输入10个整数:" << endl; for (int i = 0; i < 10; i++) { cin >> intArray[i]; } int max_idx = getMaxIndex(intArray); cout << "最大值为:" << "a[" << max_idx <<"] = " << intArray[max_idx] << endl; } else if (choice == 2) { double doubleArray[10]; cout << "请输入10个小数:" << endl; for (int i = 0; i < 10; i++) { cin >> doubleArray[i]; } int max_idx = getMaxIndex(doubleArray); cout << "最大值为:" << "a[" << max_idx <<"] = " << doubleArray[max_idx] << endl; } else if (choice == 3) { char charArray[10]; cout << "请输入10个字符:" << endl; for (int i = 0; i < 10; i++) { cin >> charArray[i]; } int max_idx = getMaxIndex(charArray); cout <<"最大值为:" << "a[" << max_idx <<"] = " << charArray[max_idx] << endl; } else { cout << "输入有误,请重新运行程序!" << endl; } return 0; } template<typename T> int getMaxIndex(T a[], int size) { int max_idx = 0; for (int i = 1; i < size; ++i) { if (a[i] > a[max_idx]) { max_idx = i; } } return max_idx; }
时间: 2024-04-03 19:32:17 浏览: 16
这段代码实现了一个可以输入不同类型数组并求出最大值的函数模板。用户可以选择输入整数、小数或字符数组,然后依次输入对应类型数组的10个元素,并通过调用 getMaxIndex 函数求出数组中最大元素的下标,最后输出最大值。
其中,getMaxIndex 函数使用了模板参数 T,表示数组元素的类型,同时也可以指定默认参数 size,表示数组大小,默认值为 10。
整个程序的流程为:先让用户选择输入数据的类型,然后根据用户的选择分别输入对应类型的数组,最后调用 getMaxIndex 函数求出最大值并输出。
相关问题
Why the following programs will cause error? #include <iostream> using namespace std; template <typename T> T max(T x, T y) { return (x > y)? x : y; } int main() { cout << max(3, 7) << endl; cout << max(3.0, 7.0) << endl; cout << max(3, 7.0) << endl; return 0; }
The program will cause an error in the third `cout` statement because the types of the arguments passed to the `max()` function are different (`int` and `double`). The `max()` function is defined as a templated function that only takes arguments of the same type.
To fix it, you can either make sure that the arguments passed to the `max()` function are of the same type, or modify the `max()` function to take arguments of different types. Here's the corrected code using the latter approach, where the `max()` function takes arguments of different types using template specialization:
```
#include <iostream>
using namespace std;
template <typename T>
T max(T x, T y) {
return (x > y)? x : y;
}
template <>
double max(double x, int y) {
return (x > y)? x : y;
}
int main() {
cout << max(3, 7) << endl;
cout << max(3.0, 7.0) << endl;
cout << max(3, 7.0) << endl;
return 0;
}
```
In this corrected code, the `max()` function is specialized for the case where the first argument is a `double` and the second argument is an `int`. This allows the third `cout` statement to work correctly.
#include <iostream>using namespace std;template<typename T>T min(T a, T b, T c) { return min(a, min(b, c));}int main() { cout << min(10, 5, 3) << endl; cout << min(10.0, 5.0, 3.0) << endl; cout << min('a', 'b', 'c') << endl; return 0;}这代码运行出错什么原因
这段代码会导致编译错误。这是因为在模板函数 `min` 中,递归调用了自身,但是没有定义递归结束的条件。因此,编译器会一直展开递归调用,直到栈空间耗尽,导致程序崩溃。为了避免这种情况,你可以将递归调用改为调用标准库中的 `std::min` 函数。修改后的代码如下:
```c++
#include <iostream>
#include <algorithm>
using namespace std;
template<typename T>
T min(T a, T b, T c) {
return min(a, min(b, c));
}
int main() {
cout << min(10, 5, 3) << endl;
cout << min(10.0, 5.0, 3.0) << endl;
cout << min('a', 'b', 'c') << endl;
return 0;
}
```
输出结果为:
```
3
3
a
```
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