#include <iostream> #include <math.h> using namespace std; void max_min(int a, int b, int c) { int m; if (a > b) { m = a; a = b; b = m; } if (a > c) { m = a; a = c; c = m; } if (b > c) { m = b; b = c; c = m; } } int main() { int t; int a, b ,c; cin >> t; for (int i = 1; i <= t; i ++) { cin >> a >> b >> c; max_min(a, b, c); if (a == b && b == c) cout << "equilateral" << endl; else if (pow (c, 2) == pow (a, 2) + pow (b, 2)) cout <<"right" << endl; else if (c >= a + b) cout << "error" << endl; else cout << "normal" << endl; } return 0; }为什么我的max_min函数不管用

你的max_min函数没有返回值，也没有改变a,b,c的值，因此在main函数中使用max_min函数并不会产生任何影响。你需要修改max_min函数，让它返回三个参数的最大值和最小值，然后在main函数中使用这些返回值来判断三角形的类型。以下是修改后的代码：

#include <iostream> 
#include <math.h>  

using namespace std;  

void max_min(int a, int b, int c, int& max_val, int& min_val) {     
    int m;     
    if (a > b)     
    {         
        m = a;         
        a = b;         
        b = m;     
    }     
    if (a > c)     
    {         
        m = a;         
        a = c;         
        c = m;     
    }     
    if (b > c)     
    {         
        m = b;         
        b = c;         
        c = m;     
    }     
    max_val = c;     
    min_val = a; 
} 

int main() {     
    int t;     
    int a, b, c;     
    cin >> t;     
    for (int i = 1; i <= t; i ++)     
    {         
        cin >> a >> b >> c;         
        int max_val, min_val;         
        max_min(a, b, c, max_val, min_val);         
        if (a == b && b == c)             
            cout << "equilateral" << endl;         
        else if (pow(c, 2) == pow(a, 2) + pow(b, 2))             
            cout << "right" << endl;         
        else if (c >= a + b)             
            cout << "error" << endl;         
        else             
            cout << "normal" << endl;     
    }     
    return 0; 
}