Ural 1029 Ministry 题解
时间: 2024-01-20 12:04:30 浏览: 28
Ural 1029 Ministry 是一道比较简单的贪心题目,以下是一种可行的思路:
首先,我们可以考虑对所有的数字进行排序,然后从小到大依次遍历这些数字。对于每一个数字,我们需要判断它是否可以被当前的部门所处理。如果可以,则将该数字分配给该部门,并更新该部门的最大处理数字;如果不可以,则需要开设一个新的部门来处理该数字,并将该数字分配给新的部门。
因此,我们需要维护一个数组 max_num,表示每个部门目前能够处理的最大数字。初始时,所有部门的 max_num 均为 0。然后,我们遍历所有的数字,对于每个数字 x,找到一个最小的 i,满足 max_num[i] < x,并将 x 分配给部门 i。如果不存在这样的 i,则开设一个新的部门来处理 x,并将其分配给新的部门。
最后,我们统计开设的部门数量即可。
代码如下:
相关问题
用代码解决这个问题The program committee of the school programming contests, which are often held at the Ural State University, is a big, joyful, and united team. In fact, they are so united that the time spent together at the university is not enough for them, so they often visit each other at their homes. In addition, they are quite athletic and like walking. Once the guardian of the traditions of the sports programming at the Ural State University decided that the members of the program committee spent too much time walking from home to home. They could have spent that time inventing and preparing new problems instead. To prove that, he wanted to calculate the average distance that the members of the program committee walked when they visited each other. The guardian took a map of Yekaterinburg, marked the houses of all the members of the program committee there, and wrote down their coordinates. However, there were so many coordinates that he wasn't able to solve that problem and asked for your help. The city of Yekaterinburg is a rectangle with the sides parallel to the coordinate axes. All the streets stretch from east to west or from north to south through the whole city, from one end to the other. The house of each member of the program committee is located strictly at the intersection of two orthogonal streets. It is known that all the members of the program committee walk only along the streets, because it is more pleasant to walk on sidewalks than on small courtyard paths. Of course, when walking from one house to another, they always choose the shortest way. All the members of the program committee visit each other equally often. Input The first line contains the number n of members of the program committee (2 ≤ n ≤ 105). The i-th of the following n lines contains space-separated coordinates xi, yi of the house of the i-th member of the program committee (1 ≤ xi, yi ≤ 106). All coordinates are integers. Output Output the average distance, rounded down to an integer, that a member of the program committee walks from his house to the house of his colleague.
Sure, I can help you with that. Here's one possible solution in Python:
```python
import math
n = int(input())
x_coords = []
y_coords = []
for i in range(n):
x, y = map(int, input().split())
x_coords.append(x)
y_coords.append(y)
x_coords.sort()
y_coords.sort()
x_median = x_coords[n // 2]
y_median = y_coords[n // 2]
total_distance = 0
for i in range(n):
total_distance += abs(x_coords[i] - x_median) + abs(y_coords[i] - y_median)
average_distance = total_distance // n
print(average_distance)
```
The idea here is to find the median x-coordinate and the median y-coordinate of all the houses, since these will be the coordinates of the "center" of the city. Then, we calculate the total distance each member of the program committee will have to walk to get to their colleague's house, by adding up the Manhattan distances between their own coordinate and the median coordinates. Finally, we divide the total distance by the number of committee members to get the average distance, rounded down to an integer. Note that we don't actually need to calculate the square root of the distances, since we only care about the integer value.
I hope this helps! Let me know if you have any questions.