a = [1,2,3,4,5] b = a[1:] b.append(a[0]) print(b)
时间: 2023-12-29 20:05:16 浏览: 87
The output of this code is:
[2, 3, 4, 5, 1]
Explanation:
- We start by defining a list `a` with the values `[1,2,3,4,5]`.
- We then create a new list `b` by slicing `a` from index 1 to the end (`a[1:]`). This means that `b` contains all the elements of `a` starting from the second one (`2,3,4,5`).
- We then use the `append()` method to add the first element of `a` (`1`) to the end of `b`.
- Finally, we print the resulting list `b`, which is `[2, 3, 4, 5, 1]`.
相关问题
约瑟夫环改错class Node: def __init__(self,data): self.data=data self.next=Noneclass linklist: def __init__(self): self.head=None self.data=None def isEmpty(self): if self.head: return False else: return True def length(self): if self.isEmpty(): return 0 else: t = self.head n = 1 while t.next: if t.next == self.head: break t = t.next n = n + 1 return n def addhead(self,data): node = Node(data) if self.isEmpty(): self.head = node self.tail = self.head else: node.next = self.head self.head = node self.tail.next = self.head def addtail(self,data): node=Node(data) if self.isEmpty(): self.addhead(data) else: t=self.head n=1 l=self.length() while n<l: n=n+1 t=t.next t.next=node node.next=self.head self.tail=node def delete(self,index): if self.isEmpty(): print("The linked list is empty") else: t = self.head l = self.length() if index == 0: self.head = t.next self.tail.next = self.head elif index == l - 1: n = 1 while n < l - 1: t = t.next n = n + 1 t.next = self.head self.tail = t elif index > l - 1: print("Out of range") elif index < 0: print("Wrong operation") else: n = 1 while n < index - 1: t = t.next n = n + 1 a = t.next.next t.next = a def insert(self,data,index): l = self.length() if index == 0 or self.isEmpty(): self.addhead(data) elif index >= l: self.addtail(data) else: node = Node(data) t = self.head n = 1 while n < index - 1: t = t.next n = n + 1 a = t.next t.next = node node.next = a def search(self,a): t=self.head for i in range(a): t=t.next return t.data def form(self,datalist): self.addhead(datalist[0]) for i in range(1,len(datalist)): self.addtail(datalist[i]) t = self.head while t.next != self.head: t = t.nextn,p=map(int,input().split(' '))data=[]p=p-1for i in range(1,n+1): data.append(i)print(data)datalist=[]for i in range(len(data)): datalist.append(int(data[i]))link=linklist()link.form(datalist)a=pb=[]while link.length()>0: b.append(link.search(a)) link.delete(a) a=a+p while a>=link.length(): a=a-link.length()print(b)
改错如下:
```python
class Node:
def __init__(self, data):
self.data = data
self.next = None
class LinkList:
def __init__(self):
self.head = None
self.tail = None
def isEmpty(self):
if self.head:
return False
else:
return True
def length(self):
if self.isEmpty():
return 0
else:
t = self.head
n = 1
while t.next:
if t.next == self.head:
break
t = t.next
n += 1
return n
def addhead(self, data):
node = Node(data)
if self.isEmpty():
self.head = node
self.tail = self.head
else:
node.next = self.head
self.head = node
self.tail.next = self.head
def addtail(self, data):
node = Node(data)
if self.isEmpty():
self.addhead(data)
else:
t = self.head
n = 1
l = self.length()
while n < l:
n += 1
t = t.next
t.next = node
node.next = self.head
self.tail = node
def delete(self, index):
if self.isEmpty():
print("The linked list is empty")
else:
t = self.head
l = self.length()
if index == 0:
self.head = t.next
self.tail.next = self.head
elif index == l - 1:
n = 1
while n < l - 1:
t = t.next
n += 1
t.next = self.head
self.tail = t
elif index > l - 1:
print("Out of range")
elif index < 0:
print("Wrong operation")
else:
n = 1
while n < index:
t = t.next
n += 1
a = t.next.next
t.next = a
def insert(self, data, index):
l = self.length()
if index == 0 or self.isEmpty():
self.addhead(data)
elif index >= l:
self.addtail(data)
else:
node = Node(data)
t = self.head
n = 1
while n < index:
t = t.next
n += 1
a = t.next
t.next = node
node.next = a
def search(self, a):
t = self.head
for i in range(a):
t = t.next
return t.data
def form(self, datalist):
self.addhead(datalist[0])
for i in range(1, len(datalist)):
self.addtail(datalist[i])
t = self.head
while t.next != self.head:
t = t.next
n, p = map(int, input().split(' '))
data = [i for i in range(1, n+1)]
print(data)
datalist = []
for i in range(len(data)):
datalist.append(data[i])
link = LinkList()
link.form(datalist)
a = p-1
b = []
while link.length() > 0:
b.append(link.search(a))
link.delete(a)
a += p-1
while a >= link.length():
a -= link.length()
print(b)
```
class TripleNode(object): def __init__(self, row=0, column=0, value=0): self.row = row self.column = column self.value = value def add_sparse_matrix(self, A, B): C = [] i = j = 0 while i < len(A) and j < len(B): if A[i].row < B[j].row: C.append(A[i]) i += 1 elif A[i].row > B[j].row: C.append(B[j]) j += 1 else: if A[i].column < B[j].column: C.append(A[i]) i += 1 elif A[i].column > B[j].column: C.append(B[j]) j += 1 else: C.append(TripleNode(A[i].row, A[i].column, A[i].value + B[j].value)) i += 1 while i < len(A): C.append(A[i]) i += 1 while j < len(B): C.append(B[j]) j += 1 return C A = [TripleNode(0, 0, 1), TripleNode(1, 1, 2)] B = [TripleNode(0, 0, 3), TripleNode(1, 1, 4)] C = add_sparse_matrix(A, B) print(C)
这段代码实现了稀疏矩阵的加法操作。其中TripleNode类表示一个三元组,分别存储稀疏矩阵的行、列和元素值。add_sparse_matrix函数接受两个稀疏矩阵A和B作为参数,返回它们的和矩阵C,C也是一个稀疏矩阵。
函数实现的思路是将A和B中的元素逐个进行比较,按照行和列的大小关系将它们合并到C中。如果A和B中有相同的行和列,则将它们对应的元素值相加。最后,将A和B中剩余的元素依次添加到C中。
在代码的末尾,我们创建了两个稀疏矩阵A和B,并将它们传递给add_sparse_matrix函数,输出其结果C。
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