def stopchineseword(segResult): if segResult!=None: segResult=segResult.split() if len(segResult)!=0: segResult=[word_item.split('/')[0] for word_item in segResult] file = open("stopwords.txt","r",encoding='utf-8') data = [] new_segResult=[] for i in file.readlines(): #从文件中读取数据并将其添加到列表中 data.append(i.strip()) for i in segResult: if i in data: #比较是否为停用词 continue else: new_segResult.append(i) return ' '.join(new_segResult) else: return " " else: return ' '
时间: 2023-06-16 16:08:13 浏览: 106
这是一个用于过滤中文停用词的函数,其输入参数为经过分词后的句子,输出为去除停用词后的句子。具体实现步骤如下:
1. 将分词结果按空格分割为单个词语;
2. 读取停用词表,将其中的词语添加到一个列表中;
3. 遍历分词结果中的每一个词语,如果该词语为停用词,则跳过该词语,否则将其添加到一个新的列表中;
4. 将新的列表中的词语用空格连接成一个字符串,并返回。
需要注意的是,该函数中的停用词表文件名为 "stopwords.txt",需要提前准备好该文件并放置在与该函数脚本相同的目录下,而且该文件必须使用 UTF-8 编码。
相关问题
约瑟夫环改错class Node: def __init__(self,data): self.data=data self.next=Noneclass linklist: def __init__(self): self.head=None self.data=None def isEmpty(self): if self.head: return False else: return True def length(self): if self.isEmpty(): return 0 else: t = self.head n = 1 while t.next: if t.next == self.head: break t = t.next n = n + 1 return n def addhead(self,data): node = Node(data) if self.isEmpty(): self.head = node self.tail = self.head else: node.next = self.head self.head = node self.tail.next = self.head def addtail(self,data): node=Node(data) if self.isEmpty(): self.addhead(data) else: t=self.head n=1 l=self.length() while n<l: n=n+1 t=t.next t.next=node node.next=self.head self.tail=node def delete(self,index): if self.isEmpty(): print("The linked list is empty") else: t = self.head l = self.length() if index == 0: self.head = t.next self.tail.next = self.head elif index == l - 1: n = 1 while n < l - 1: t = t.next n = n + 1 t.next = self.head self.tail = t elif index > l - 1: print("Out of range") elif index < 0: print("Wrong operation") else: n = 1 while n < index - 1: t = t.next n = n + 1 a = t.next.next t.next = a def insert(self,data,index): l = self.length() if index == 0 or self.isEmpty(): self.addhead(data) elif index >= l: self.addtail(data) else: node = Node(data) t = self.head n = 1 while n < index - 1: t = t.next n = n + 1 a = t.next t.next = node node.next = a def search(self,a): t=self.head for i in range(a): t=t.next return t.data def form(self,datalist): self.addhead(datalist[0]) for i in range(1,len(datalist)): self.addtail(datalist[i]) t = self.head while t.next != self.head: t = t.nextn,p=map(int,input().split(' '))data=[]p=p-1for i in range(1,n+1): data.append(i)print(data)datalist=[]for i in range(len(data)): datalist.append(int(data[i]))link=linklist()link.form(datalist)a=pb=[]while link.length()>0: b.append(link.search(a)) link.delete(a) a=a+p while a>=link.length(): a=a-link.length()print(b)
改错如下:
```python
class Node:
def __init__(self, data):
self.data = data
self.next = None
class LinkList:
def __init__(self):
self.head = None
self.tail = None
def isEmpty(self):
if self.head:
return False
else:
return True
def length(self):
if self.isEmpty():
return 0
else:
t = self.head
n = 1
while t.next:
if t.next == self.head:
break
t = t.next
n += 1
return n
def addhead(self, data):
node = Node(data)
if self.isEmpty():
self.head = node
self.tail = self.head
else:
node.next = self.head
self.head = node
self.tail.next = self.head
def addtail(self, data):
node = Node(data)
if self.isEmpty():
self.addhead(data)
else:
t = self.head
n = 1
l = self.length()
while n < l:
n += 1
t = t.next
t.next = node
node.next = self.head
self.tail = node
def delete(self, index):
if self.isEmpty():
print("The linked list is empty")
else:
t = self.head
l = self.length()
if index == 0:
self.head = t.next
self.tail.next = self.head
elif index == l - 1:
n = 1
while n < l - 1:
t = t.next
n += 1
t.next = self.head
self.tail = t
elif index > l - 1:
print("Out of range")
elif index < 0:
print("Wrong operation")
else:
n = 1
while n < index:
t = t.next
n += 1
a = t.next.next
t.next = a
def insert(self, data, index):
l = self.length()
if index == 0 or self.isEmpty():
self.addhead(data)
elif index >= l:
self.addtail(data)
else:
node = Node(data)
t = self.head
n = 1
while n < index:
t = t.next
n += 1
a = t.next
t.next = node
node.next = a
def search(self, a):
t = self.head
for i in range(a):
t = t.next
return t.data
def form(self, datalist):
self.addhead(datalist[0])
for i in range(1, len(datalist)):
self.addtail(datalist[i])
t = self.head
while t.next != self.head:
t = t.next
n, p = map(int, input().split(' '))
data = [i for i in range(1, n+1)]
print(data)
datalist = []
for i in range(len(data)):
datalist.append(data[i])
link = LinkList()
link.form(datalist)
a = p-1
b = []
while link.length() > 0:
b.append(link.search(a))
link.delete(a)
a += p-1
while a >= link.length():
a -= link.length()
print(b)
```
优化提升下列代码效率:class User: def init(self): self.id = 0 self.perfect = 0 self.rank = 0 self.mk = -1 self.grade = [0, -1, -1, -1, -1, -1] def lt(self, other): if self.grade[0] != other.grade[0]: return self.grade[0] > other.grade[0] elif self.perfect != other.perfect: return self.perfect > other.perfect else: return self.id < other.id if name == "main": N, K, M = map(int, input().split()) p = [0] + list(map(int, input().split())) u = [None] * (N + 1) idx = [] for i in range(M): tmp, pid, tmpgrade = map(int, input().split()) if not u[tmp]: u[tmp] = User() u[tmp].id = tmp if tmpgrade != -1: u[tmp].mk = 1 else: tmpgrade = 0 if tmpgrade > u[tmp].grade[pid]: u[tmp].grade[pid] = tmpgrade if not idx.contains(tmp): idx.append(tmp) for i in range(len(idx)): for j in range(1, K + 1): if u[idx[i]].grade[j] >= 0: u[idx[i]].grade[0] += u[idx[i]].grade[j] if u[idx[i]].grade[j] == p[j]: u[idx[i]].perfect += 1 al = sorted([u[i] for i in idx if u[i].mk > 0]) for i in range(len(al)): if i == 0: al[i].rank = 1 else: if al[i].grade[0] == al[i - 1].grade[0]: al[i].rank = al[i - 1].rank else: al[i].rank = i + 1 for i in range(len(al)): print("{} {:05d}".format(al[i].rank, al[i].id), end="") for j in range(K + 1): if al[i].grade[j] >= 0: print(" {:d}".format(al[i].grade[j]), end="") else: print(" -", end="") if i != len(al) - 1: print()
首先,可以使用 set() 代替 idx 列表,因为我们只需要判断一个元素是否在集合中。这样可以减少重复的判断。
其次,在 User 类的初始化函数中,可以直接将属性设置为默认值,而不是在每个属性上进行赋值。
另外,在循环中,可以使用 enumerate() 函数代替 range() 函数和下标变量,这样可以避免手动维护下标变量。
最后,在计算排名时,可以使用 itertools.groupby() 函数实现,这样可以避免手动维护排名和比较。
下面是优化后的代码:
```python
import itertools
class User:
def __init__(self):
self.id = 0
self.perfect = 0
self.rank = 0
self.mk = -1
self.grade = [0, -1, -1, -1, -1, -1]
def lt(self, other):
if self.grade[0] != other.grade[0]:
return self.grade[0] > other.grade[0]
elif self.perfect != other.perfect:
return self.perfect > other.perfect
else:
return self.id < other.id
if __name__ == "__main__":
N, K, M = map(int, input().split())
p = [0] + list(map(int, input().split()))
u = [None] * (N + 1)
idx = set()
for i in range(M):
tmp, pid, tmpgrade = map(int, input().split())
if not u[tmp]:
u[tmp] = User()
u[tmp].id = tmp
if tmpgrade != -1:
u[tmp].mk = 1
else:
tmpgrade = 0
if tmpgrade > u[tmp].grade[pid]:
u[tmp].grade[pid] = tmpgrade
idx.add(tmp)
for i, user in enumerate(u):
if user and user.mk > 0:
user.grade[0] = sum(user.grade[j] for j in range(1, K + 1) if user.grade[j] >= 0)
user.perfect = sum(user.grade[j] == p[j] for j in range(1, K + 1))
al = sorted([user for user in u if user and user.mk > 0], key=lambda x: (-x.grade[0], -x.perfect, x.id))
for rank, group in itertools.groupby(al, key=lambda x: (x.grade[0], x.perfect)):
for user in group:
user.rank = rank
for user in sorted(list(group), key=lambda x: x.id):
print("{:d} {:05d}".format(user.rank, user.id), end="")
for j in range(1, K + 1):
if user.grade[j] >= 0:
print(" {:d}".format(user.grade[j]), end="")
else:
print(" -", end="")
print()
```
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