def stopchineseword(segResult): if segResult!=None: segResult=segResult.split() if len(segResult)!=0: segResult=[word_item.split('/')[0] for word_item in segResult] file = open("stopwords.txt","r",encoding='utf-8') data = [] new_segResult=[] for i in file.readlines(): #从文件中读取数据并将其添加到列表中 data.append(i.strip()) for i in segResult: if i in data: #比较是否为停用词 continue else: new_segResult.append(i) return ' '.join(new_segResult) else: return " " else: return ' '

这是一个用于过滤中文停用词的函数，其输入参数为经过分词后的句子，输出为去除停用词后的句子。具体实现步骤如下：

1. 将分词结果按空格分割为单个词语；
2. 读取停用词表，将其中的词语添加到一个列表中；
3. 遍历分词结果中的每一个词语，如果该词语为停用词，则跳过该词语，否则将其添加到一个新的列表中；
4. 将新的列表中的词语用空格连接成一个字符串，并返回。

需要注意的是，该函数中的停用词表文件名为 "stopwords.txt"，需要提前准备好该文件并放置在与该函数脚本相同的目录下，而且该文件必须使用 UTF-8 编码。

相关问题

约瑟夫环改错class Node: def __init__(self,data): self.data=data self.next=Noneclass linklist: def __init__(self): self.head=None self.data=None def isEmpty(self): if self.head: return False else: return True def length(self): if self.isEmpty(): return 0 else: t = self.head n = 1 while t.next: if t.next == self.head: break t = t.next n = n + 1 return n def addhead(self,data): node = Node(data) if self.isEmpty(): self.head = node self.tail = self.head else: node.next = self.head self.head = node self.tail.next = self.head def addtail(self,data): node=Node(data) if self.isEmpty(): self.addhead(data) else: t=self.head n=1 l=self.length() while n<l: n=n+1 t=t.next t.next=node node.next=self.head self.tail=node def delete(self,index): if self.isEmpty(): print("The linked list is empty") else: t = self.head l = self.length() if index == 0: self.head = t.next self.tail.next = self.head elif index == l - 1: n = 1 while n < l - 1: t = t.next n = n + 1 t.next = self.head self.tail = t elif index > l - 1: print("Out of range") elif index < 0: print("Wrong operation") else: n = 1 while n < index - 1: t = t.next n = n + 1 a = t.next.next t.next = a def insert(self,data,index): l = self.length() if index == 0 or self.isEmpty(): self.addhead(data) elif index >= l: self.addtail(data) else: node = Node(data) t = self.head n = 1 while n < index - 1: t = t.next n = n + 1 a = t.next t.next = node node.next = a def search(self,a): t=self.head for i in range(a): t=t.next return t.data def form(self,datalist): self.addhead(datalist[0]) for i in range(1,len(datalist)): self.addtail(datalist[i]) t = self.head while t.next != self.head: t = t.nextn,p=map(int,input().split(' '))data=[]p=p-1for i in range(1,n+1): data.append(i)print(data)datalist=[]for i in range(len(data)): datalist.append(int(data[i]))link=linklist()link.form(datalist)a=pb=[]while link.length()>0: b.append(link.search(a)) link.delete(a) a=a+p while a>=link.length(): a=a-link.length()print(b)

改错如下：

class Node:
    def __init__(self, data):
        self.data = data
        self.next = None

class LinkList:
    def __init__(self):
        self.head = None
        self.tail = None
    
    def isEmpty(self):
        if self.head:
            return False
        else:
            return True
    
    def length(self):
        if self.isEmpty():
            return 0
        else:
            t = self.head
            n = 1
            while t.next:
                if t.next == self.head:
                    break
                t = t.next
                n += 1
            return n
    
    def addhead(self, data):
        node = Node(data)
        if self.isEmpty():
            self.head = node
            self.tail = self.head
        else:
            node.next = self.head
            self.head = node
            self.tail.next = self.head
    
    def addtail(self, data):
        node = Node(data)
        if self.isEmpty():
            self.addhead(data)
        else:
            t = self.head
            n = 1
            l = self.length()
            while n < l:
                n += 1
                t = t.next
            t.next = node
            node.next = self.head
            self.tail = node
    
    def delete(self, index):
        if self.isEmpty():
            print("The linked list is empty")
        else:
            t = self.head
            l = self.length()
            if index == 0:
                self.head = t.next
                self.tail.next = self.head
            elif index == l - 1:
                n = 1
                while n < l - 1:
                    t = t.next
                    n += 1
                t.next = self.head
                self.tail = t
            elif index > l - 1:
                print("Out of range")
            elif index < 0:
                print("Wrong operation")
            else:
                n = 1
                while n < index:
                    t = t.next
                    n += 1
                a = t.next.next
                t.next = a
    
    def insert(self, data, index):
        l = self.length()
        if index == 0 or self.isEmpty():
            self.addhead(data)
        elif index >= l:
            self.addtail(data)
        else:
            node = Node(data)
            t = self.head
            n = 1
            while n < index:
                t = t.next
                n += 1
            a = t.next
            t.next = node
            node.next = a
    
    def search(self, a):
        t = self.head
        for i in range(a):
            t = t.next
        return t.data
    
    def form(self, datalist):
        self.addhead(datalist[0])
        for i in range(1, len(datalist)):
            self.addtail(datalist[i])
        t = self.head
        while t.next != self.head:
            t = t.next

n, p = map(int, input().split(' '))
data = [i for i in range(1, n+1)]
print(data)

datalist = []
for i in range(len(data)):
    datalist.append(data[i])

link = LinkList()
link.form(datalist)

a = p-1
b = []
while link.length() > 0:
    b.append(link.search(a))
    link.delete(a)
    a += p-1
    while a >= link.length():
        a -= link.length()

print(b)

定义二叉搜索树节点类 class TreeNode: def init(self, val): self.val = val self.left = None self.right = None # 插入节点 def insert(root, val): if not root: return TreeNode(val) if val < root.val: root.left = insert(root.left, val) else: root.right = insert(root.right, val) return root # 顺序遍历二叉搜索树 def inorderTraversal(root): res = [] if not root: return res res += inorderTraversal(root.left) res.append(root.val) res += inorderTraversal(root.right) return res # 将二叉搜索树转换为双向循环链表 def treeToDoublyList(root): if not root: return None inorder = inorderTraversal(root) head = cur = TreeNode(None) for val in inorder: cur.right = TreeNode(val) cur.right.left = cur cur = cur.right head.right.left = cur cur.right = head.right return head.right # 打印二叉搜索树 def printTree(root, space): if not root: return space += 5 printTree(root.right, space) print(' ' * space, root.val) printTree(root.left, space) # 打印双向循环链表 def printList(head): if not head: return print(head.val, end=' <--> ') cur = head.right while cur != head and cur.right != head: print(cur.val, end=' <--> ') cur = cur.right if cur.right == head: print(cur.val) cur = cur.right length = 7 * len(values) - 7 print('^' + ' '*length + '^') print('|' + ' '*length + '|') print('\' + '-'*length + '/') print() # 测试 if name == 'main': root = None values = input('请输入要插入的节点值，以空格分隔：').split() for val in values: root = insert(root, val) bstree = root print('Binary Search Tree:') printTree(bstree, 0) dllist = treeToDoublyList(bstree) print('Doubly Linked List:') printList(dllist) print('------------------------menu--------------------------- \n' '|0.escape \n' '|1.input the BSTree elements \n' '|2.traverse the BSTree \n' '|3.print the LinkedList \n' '|4.output all the elements by forward and backward order\n')将menu函数的作用融入代码中

好的，以下是将menu函数融入代码中的版本：

class TreeNode:
    def __init__(self, val):
        self.val = val
        self.left = None
        self.right = None

def insert(root, val):
    if not root:
        return TreeNode(val)
    if val < root.val:
        root.left = insert(root.left, val)
    else:
        root.right = insert(root.right, val)
    return root

def inorderTraversal(root):
    res = []
    if not root:
        return res
    res += inorderTraversal(root.left)
    res.append(root.val)
    res += inorderTraversal(root.right)
    return res

def treeToDoublyList(root):
    if not root:
        return None
    inorder = inorderTraversal(root)
    head = cur = TreeNode(None)
    for val in inorder:
        cur.right = TreeNode(val)
        cur.right.left = cur
        cur = cur.right
    head.right.left = cur
    cur.right = head.right
    return head.right

def printTree(root, space):
    if not root:
        return
    space += 5
    printTree(root.right, space)
    print(' ' * space, root.val)
    printTree(root.left, space)

def printList(head):
    if not head:
        return
    print(head.val, end=' <--> ')
    cur = head.right
    while cur != head and cur.right != head:
        print(cur.val, end=' <--> ')
        cur = cur.right
    if cur.right == head:
        print(cur.val)
    cur = cur.right

def menu():
    while True:
        choice = input('请输入您的选择：')
        if choice == '0':
            break
        elif choice == '1':
            values = input('请输入要插入的节点值，以空格分隔：').split()
            for val in values:
                root = insert(root, val)
            bstree = root
            print('Binary Search Tree:')
            printTree(bstree, 0)
        elif choice == '2':
            inorder = inorderTraversal(root)
            print('Inorder Traversal:')
            print(inorder)
        elif choice == '3':
            dllist = treeToDoublyList(root)
            print('Doubly Linked List:')
            printList(dllist)
        elif choice == '4':
            inorder = inorderTraversal(root)
            forward = 'Forward Order: ' + ' <--> '.join(inorder)
            backward = 'Backward Order: ' + ' <--> '.join(inorder[::-1])
            print(forward)
            print(backward)
        else:
            print('无效的选项，请重新选择！')

if __name__ == '__main__':
    root = None
    menu()

这个版本中，我们将menu函数放在了主函数外面，并且使用了一个while循环，让用户可以在一个菜单中进行多次操作。在用户选择了不同的选项之后，代码会执行相应的函数并输出结果。