Expected 'Iterator' as the return annotation for `__iter__` of SMILESParser, but found typing.Any
时间: 2023-12-03 12:43:17 浏览: 155
This error message means that in the `SMILESParser` class, the `__iter__` method should have a return annotation of `Iterator`, but instead it has been annotated with `typing.Any`.
To fix this error, you should change the return annotation of the `__iter__` method to `Iterator`. Here's an example:
```python
from typing import Iterator
class SMILESParser:
def __init__(self, smiles: str):
self.smiles = smiles
def __iter__(self) -> Iterator:
# implement your iterator here
yield ...
```
By annotating the `__iter__` method with `Iterator`, you are indicating that this method returns an iterator object.
相关问题
TypeError: Expected 'Iterator' as the return annotation for `__iter__` of SMILESParser, but found typing.Any
我不确定我是否理解您的问题,请问您可以再解释一下吗?如果您在使用SMILESParser时遇到了TypeError,请检查是否在定义__iter__方法时正确地使用了迭代器作为返回注释。如果您仍然无法解决问题,请查看错误消息以获取更多信息。
报错如下“ Expected 'Iterator' as the return annotation for `__iter__` of SMILESParser, but found typing.Any”,是什么问题应该如何修改
这个报错是因为你在定义 `SMILESParser` 类时,使用了 `typing.Any` 作为 `__iter__` 方法的返回注解,但是实际上应该使用 `typing.Iterator`。
要修复这个问题,你需要将 `typing.Any` 替换为 `typing.Iterator`,代码示例如下:
```python
import typing
class SMILESParser:
def __init__(self, smiles: str):
self.smiles = smiles
def __iter__(self) -> typing.Iterator:
# your implementation here
```
这样修改后就不会再出现这个报错了。
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