安卓8代码休眠状态下双击触摸时唤醒屏幕

实现安卓8代码休眠状态下双击触摸时唤醒屏幕的方法可以使用以下代码：

1. 在 AndroidManifest.xml 文件中添加权限：

<uses-permission android:name="android.permission.WAKE_LOCK" />

2. 添加一个 BroadcastReceiver 类来接收广播：

public class ScreenReceiver extends BroadcastReceiver {
    private static final int WAKELOCK_TIMEOUT = 5000;
    private PowerManager.WakeLock mWakeLock;

    @Override
    public void onReceive(Context context, Intent intent) {
        if (intent.getAction().equals(Intent.ACTION_SCREEN_OFF)) {
            acquireWakeLock(context);
        } else if (intent.getAction().equals(Intent.ACTION_SCREEN_ON)) {
            releaseWakeLock();
        }
    }

    private void acquireWakeLock(Context context) {
        PowerManager pm = (PowerManager) context.getSystemService(Context.POWER_SERVICE);
        mWakeLock = pm.newWakeLock(PowerManager.SCREEN_DIM_WAKE_LOCK | PowerManager.ACQUIRE_CAUSES_WAKEUP, "ScreenReceiver");
        mWakeLock.acquire(WAKELOCK_TIMEOUT);
    }

    private void releaseWakeLock() {
        if (mWakeLock != null) {
            mWakeLock.release();
            mWakeLock = null;
        }
    }
}

3. 在 Activity 中注册 BroadcastReceiver：

private ScreenReceiver mScreenReceiver;

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);

    mScreenReceiver = new ScreenReceiver();
    IntentFilter filter = new IntentFilter(Intent.ACTION_SCREEN_OFF);
    filter.addAction(Intent.ACTION_SCREEN_ON);
    registerReceiver(mScreenReceiver, filter);
}

@Override
protected void onDestroy() {
    super.onDestroy();
    unregisterReceiver(mScreenReceiver);
}

这样，当用户双击屏幕时，广播接收器将捕获到 ACTION_SCREEN_OFF 广播并使用 PowerManager.WakeLock 唤醒设备。当用户再次触摸屏幕时，广播接收器将捕获到 ACTION_SCREEN_ON 广播并释放 WakeLock。