三个线程,分别输出a,b,c。各输出100次,要求按abc的顺序输出 java

这个问题可以直接回答。可以使用synchronized关键字来同步三个线程，确保按照abc的顺序输出。代码如下：

class PrintThread implements Runnable {
    private static Object lock = new Object(); // 静态锁
    private String toPrint; // 要输出的字母
    private int times; // 输出次数

    public PrintThread(String toPrint, int times) {
        this.toPrint = toPrint;
        this.times = times;
    }

    public void run() {
        for (int i = 0; i < times; i++) {
            synchronized (lock) {
                while (!toPrint.equals(curLetter)) { // 不是当前字母，等待
                    try {
                        lock.wait();
                    } catch (InterruptedException e) {
                        e.printStackTrace();
                    }
                }

                System.out.print(toPrint); // 输出当前字母
                if (toPrint.equals("c")) System.out.println(); // 输出完c后换行

                switch (toPrint) { // 更改当前字母
                    case "a":
                        curLetter = "b";
                        break;
                    case "b":
                        curLetter = "c";
                        break;
                    case "c":
                        curLetter = "a";
                        break;
                }

                lock.notifyAll(); // 唤醒等待线程
            }
        }
    }
}

public class Test {
    private static String curLetter = "a"; // 当前要输出的字母

    public static void main(String[] args) {
        new Thread(new PrintThread("a", 100)).start();
        new Thread(new PrintThread("b", 100)).start();
        new Thread(new PrintThread("c", 100)).start();
    }
}

笑话：为什么码农喜欢喝奶茶呢？因为奶茶里有异步。