-共有1000张电影票,可以在两个窗口领取,假设每次领取的时间为3000毫秒 java代码

下面是一个简单的Java代码示例，用于模拟两个窗口同时领取1000张电影票的情况，每次领取的时间为3000毫秒：

public class TicketCounter {
    public static void main(String[] args) {
        int numTickets = 1000;
        int numWindows = 2;
        int ticketsPerWindow = numTickets / numWindows;

        for (int i = 1; i <= numWindows; i++) {
            Window window = new Window(i, ticketsPerWindow);
            window.start();
        }
    }
}

class Window extends Thread {
    private int windowNum;
    private int numTickets;

    public Window(int windowNum, int numTickets) {
        this.windowNum = windowNum;
        this.numTickets = numTickets;
    }

    public void run() {
        for (int i = 1; i <= numTickets; i++) {
            System.out.println("Window " + windowNum + " is processing ticket " + i);
            try {
                Thread.sleep(3000);
            } catch (InterruptedException e) {
                e.printStackTrace();
            }
        }
    }
}

该代码将1000张电影票分配给两个窗口，每个窗口领取的票数为500。Window类代表一个窗口，它在run()方法中循环处理票。每次处理票时，线程将休眠3000毫秒以模拟领取时间。在循环结束时，该窗口将完成所有票的处理。