请提供pytorch的示例
时间: 2023-11-03 16:04:22 浏览: 32
以下是一个基于PyTorch实现的Faster R-CNN目标检测模型示例:
```python
import torch
import torchvision
import torchvision.transforms as transforms
import torch.nn as nn
import torch.optim as optim
# 定义模型
class FasterRCNN(nn.Module):
def __init__(self):
super(FasterRCNN, self).__init__()
self.backbone = torchvision.models.vgg16(pretrained=True)
self.rpn = nn.Sequential(
nn.Conv2d(512, 512, kernel_size=3, stride=1, padding=1),
nn.ReLU(),
nn.Conv2d(512, 512, kernel_size=3, stride=1, padding=1),
nn.ReLU(),
nn.Conv2d(512, 512, kernel_size=3, stride=1, padding=1),
nn.ReLU(),
nn.Conv2d(512, 512, kernel_size=3, stride=1, padding=1),
nn.ReLU(),
nn.Conv2d(512, 9 * 4, kernel_size=1, stride=1, padding=0),
)
self.roi_pooling = nn.AdaptiveMaxPool2d((7, 7))
self.classifier = nn.Sequential(
nn.Linear(7 * 7 * 512, 4096),
nn.ReLU(),
nn.Linear(4096, 4096),
nn.ReLU(),
nn.Linear(4096, 21),
)
def forward(self, x):
x = self.backbone.features(x)
rpn_output = self.rpn(x)
roi_boxes = self.convert_to_roi_boxes(rpn_output)
roi_features = self.roi_pooling(x, roi_boxes)
roi_features = roi_features.view(roi_features.size(0), -1)
output = self.classifier(roi_features)
return output
def convert_to_roi_boxes(self, rpn_output):
rpn_output = rpn_output.permute(0, 2, 3, 1).contiguous().view(-1, 4)
roi_boxes = torch.zeros((rpn_output.size(0), 4))
roi_boxes[:, 0] = rpn_output[:, 0] - 0.5 * rpn_output[:, 2]
roi_boxes[:, 1] = rpn_output[:, 1] - 0.5 * rpn_output[:, 3]
roi_boxes[:, 2] = rpn_output[:, 0] + 0.5 * rpn_output[:, 2]
roi_boxes[:, 3] = rpn_output[:, 1] + 0.5 * rpn_output[:, 3]
return roi_boxes
# 准备数据
transform = transforms.Compose(
[transforms.ToTensor(),
transforms.Normalize((0.5, 0.5, 0.5), (0.5, 0.5, 0.5))])
trainset = torchvision.datasets.CIFAR10(root='./data', train=True,
download=True, transform=transform)
trainloader = torch.utils.data.DataLoader(trainset, batch_size=4,
shuffle=True, num_workers=2)
# 定义损失函数和优化器
criterion = nn.CrossEntropyLoss()
optimizer = optim.SGD(net.parameters(), lr=0.001, momentum=0.9)
# 训练模型
for epoch in range(2): # 2个epoch
running_loss = 0.0
for i, data in enumerate(trainloader, 0):
inputs, labels = data
optimizer.zero_grad()
outputs = net(inputs)
loss = criterion(outputs, labels)
loss.backward()
optimizer.step()
running_loss += loss.item()
if i % 2000 == 1999: # 每2000个小批量数据打印一次损失值
print('[%d, %5d] loss: %.3f' %
(epoch + 1, i + 1, running_loss / 2000))
running_loss = 0.0
print('Finished Training')
```
注意:以上示例中的模型和数据仅供参考,实际应用中需要根据具体场景进行调整和优化。
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