android Java代码实现监听到开机后延迟一秒给设置发启动广播

您可以在 AndroidManifest.xml 文件中注册一个开机启动接收器，然后在接收器中使用 Handler.postDelayed() 实现延迟一秒后发送广播的功能。以下是实现的示例代码：

1. 在 AndroidManifest.xml 文件中注册接收器：

<receiver android:name=".BootReceiver">
    <intent-filter>
        <action android:name="android.intent.action.BOOT_COMPLETED" />
    </intent-filter>
</receiver>

2. 创建 BootReceiver 类，继承 BroadcastReceiver：

public class BootReceiver extends BroadcastReceiver {
    private static final String TAG = "BootReceiver";

    @Override
    public void onReceive(Context context, Intent intent) {
        if (intent.getAction().equals(Intent.ACTION_BOOT_COMPLETED)) {
            Toast.makeText(context, "Boot completed!", Toast.LENGTH_LONG).show();

            // 延迟一秒后发送启动广播
            new Handler().postDelayed(new Runnable() {
                @Override
                public void run() {
                    Intent startIntent = new Intent("com.example.action.START");
                    context.sendBroadcast(startIntent);
                    Log.d(TAG, "Broadcast sent!");
                }
            }, 1000);
        }
    }
}

3. 在需要接收启动广播的组件中注册广播接收器：

<receiver android:name=".StartReceiver">
    <intent-filter>
        <action android:name="com.example.action.START" />
    </intent-filter>
</receiver>

4. 创建 StartReceiver 类，继承 BroadcastReceiver：

public class StartReceiver extends BroadcastReceiver {
    private static final String TAG = "StartReceiver";

    @Override
    public void onReceive(Context context, Intent intent) {
        Toast.makeText(context, "Start received!", Toast.LENGTH_LONG).show();
        Log.d(TAG, "Start received!");
    }
}

这样，当设备启动完成后，BootReceiver 接收器会收到 BOOT_COMPLETED 的广播，然后延迟一秒后发送一个名为 "com.example.action.START" 的广播，StartReceiver 接收器会收到该广播并弹出一个 Toast 消息。