python启发式搜索算法解决八数码问题
时间: 2023-12-01 09:42:16 浏览: 128
启发式搜索算法求解八数码问题
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以下是使用Python实现启发式搜索算法解决八数码问题的步骤:
1.定义状态类,包含当前状态、父状态、深度、评估函数值等属性。
2.定义评估函数,用于评估当前状态到目标状态的距离。
3.定义启发式搜索函数,使用优先队列存储状态,每次取出评估函数值最小的状态进行扩展,直到找到目标状态或者队列为空。
4.定义状态扩展函数,生成当前状态的所有可能子状态。
5.判断初始状态是否有解,若无解则无法进行搜索。
6.使用Pygame库实现图形化界面,方便用户进行交互。
以下是一个简单的Python代码示例,实现了八数码问题的启发式搜索算法:
```python
import pygame
from queue import PriorityQueue
# 定义状态类
class State:
def __init__(self, state, parent, depth, f):
self.state = state
self.parent = parent
self.depth = depth
self.f = f
def __lt__(self, other):
return self.f < other.f
# 定义评估函数
def heuristic(state, target):
distance = 0
for i in range(3):
for j in range(3):
if state[i][j] != target[i][j]:
distance += 1
return distance
# 定义状态扩展函数
def expand(state):
states = []
for i in range(3):
for j in range(3):
if state[i][j] == 0:
if i > 0:
new_state = [row[:] for row in state]
new_state[i][j], new_state[i-1][j] = new_state[i-1][j], new_state[i][j]
states.append(new_state)
if i < 2:
new_state = [row[:] for row in state]
new_state[i][j], new_state[i+1][j] = new_state[i+1][j], new_state[i][j]
states.append(new_state)
if j > 0:
new_state = [row[:] for row in state]
new_state[i][j], new_state[i][j-1] = new_state[i][j-1], new_state[i][j]
states.append(new_state)
if j < 2:
new_state = [row[:] for row in state]
new_state[i][j], new_state[i][j+1] = new_state[i][j+1], new_state[i][j]
states.append(new_state)
return states
# 定义启发式搜索函数
def a_star(start, target):
queue = PriorityQueue()
queue.put(State(start, None, 0, heuristic(start, target)))
visited = set()
while not queue.empty():
current = queue.get()
if current.state == target:
path = []
while current:
path.append(current.state)
current = current.parent
return path[::-1]
visited.add(str(current.state))
for state in expand(current.state):
if str(state) not in visited:
queue.put(State(state, current, current.depth+1, current.depth+1+heuristic(state, target)))
return None
# 判断初始状态是否有解
def solvable(state):
inversion = 0
for i in range(9):
for j in range(i+1, 9):
if state[i//3][i%3] and state[j//3][j%3] and state[i//3][i%3] > state[j//3][j%3]:
inversion += 1
return inversion % 2 == 0
# 初始化Pygame
pygame.init()
size = width, height = 300, 300
screen = pygame.display.set_mode(size)
pygame.display.set_caption("八数码问题")
# 定义颜色
white = (255, 255, 255)
black = (0, 0, 0)
gray = (128, 128, 128)
# 定义字体
font = pygame.font.SysFont("Arial", 20)
# 定义方块
class Block:
def __init__(self, value, row, col):
self.value = value
self.row = row
self.col = col
def draw(self):
rect = pygame.Rect(self.col*100, self.row*100, 100, 100)
pygame.draw.rect(screen, white, rect)
pygame.draw.rect(screen, black, rect, 2)
if self.value:
text = font.render(str(self.value), True, black)
text_rect = text.get_rect(center=rect.center)
screen.blit(text, text_rect)
# 定义游戏主循环
def main_loop():
start_state = [[1, 2, 3], [4, 5, 6], [7, 8, 0]]
target_state = [[1, 2, 3], [4, 5, 6], [7, 8, 0]]
while True:
for event in pygame.event.get():
if event.type == pygame.QUIT:
pygame.quit()
return
if event.type == pygame.MOUSEBUTTONUP:
pos = pygame.mouse.get_pos()
row, col = pos[1]//100, pos[0]//100
if start_state[row][col] == 0:
continue
for state in a_star(start_state, target_state):
for i in range(3):
for j in range(3):
if state[i][j] == start_state[row][col]:
start_state[row][col], start_state[i][j] = start_state[i][j], start_state[row][col]
break
draw_board(start_state)
pygame.display.flip()
pygame.time.wait(100)
if start_state == target_state:
text = font.render("You Win!", True, black)
text_rect = text.get_rect(center=(width//2, height//2))
screen.blit(text, text_rect)
pygame.display.flip()
pygame.time.wait(1000)
start_state = [[1, 2, 3], [4, 5, 6], [7, 8, 0]]
draw_board(start_state)
pygame.display.flip()
# 定义绘制游戏界面函数
def draw_board(state):
screen.fill(gray)
for i in range(3):
for j in range(3):
block = Block(state[i][j], i, j)
block.draw()
# 判断初始状态是否有解
if not solvable(start_state):
print("无解")
else:
draw_board(start_state)
pygame.display.flip()
main_loop()
```
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