给出蜘蛛纸牌的Python代码
时间: 2023-11-19 08:10:59 浏览: 39
以下是蜘蛛纸牌的Python代码:
```python
import random
# Initialize variables
suits = ['♥', '♦', '♠', '♣']
ranks = ['A', '2', '3', '4', '5', '6', '7', '8', '9', '10', 'J', 'Q', 'K']
deck = [(rank, suit) for rank in ranks for suit in suits]
random.shuffle(deck)
tableaus = [[deck.pop() for _ in range(i+1)] for i in range(7)]
foundations = [[] for _ in range(4)]
waste = []
# Define functions
def print_game():
print('\nFoundations:')
for foundation in foundations:
print(foundation)
print('\nTableaus:')
for tableau in tableaus:
print(tableau)
print('\nWaste:', waste)
print()
def can_move_card(card, destination):
if len(destination) == 0:
return card[0] == 'K'
else:
destination_card = destination[-1]
return (card[1] != destination_card[1]) and (card[0] == destination_card[0]-1)
def move_card(source, destination):
card = source.pop()
destination.append(card)
def deal_cards():
nonlocal deck, waste
if len(deck) == 0:
deck = waste[::-1]
waste = []
card = deck.pop()
waste.append(card)
def check_win():
for foundation in foundations:
if len(foundation) != 13:
return False
return True
# Play game
while not check_win():
print_game()
move = input('Enter move (e.g. T1F for tableau 1 to foundation): ')
if move == 'deal':
deal_cards()
elif move[0] == 'T':
tableau_num = int(move[1])
if len(move) == 2:
deal_cards()
else:
destination = move[3]
destination_num = int(destination)
if can_move_card(tableaus[tableau_num-1][-1], foundations[destination_num-1]):
move_card(tableaus[tableau_num-1], foundations[destination_num-1])
else:
print('Invalid move')
elif move[0] == 'W':
destination = move[2]
destination_num = int(destination)
if can_move_card(waste[-1], foundations[destination_num-1]):
move_card(waste, foundations[destination_num-1])
else:
print('Invalid move')
else:
print('Invalid move')
print('You win!')
```
运行代码后,可以输入以下命令:
- `deal`: 将底牌中的牌放入荒地
- `T1F`: 将第1个台面上的牌移动到第1个基础牌堆中
- `WF2`: 将荒地上的牌移动到第2个基础牌堆中
注意,输入的命令是区分大小写的。