int count = 0; for (int i = 1; i <= 10; i++) { if (i == 5) { continue; } for (int j = 0; j <= 10; j++) { if (j == 5) { break; } count++; } } System.out.println(count);详细的解释一下这题的运算过程
时间: 2024-02-10 21:09:00 浏览: 28
这段代码的运行过程如下:
1. 初始化一个变量count为0。
2. 从1循环到10,每次循环一个变量i。如果i等于5,执行continue语句,跳过本次循环。
3. 对于每个i值,从0循环到10,每次循环一个变量j。如果j等于5,执行break语句,跳出内层循环。
4. 对于每个不满足break条件的j值,执行一次count++,即将count的值加1。
5. 内层循环结束后,回到外层循环,重复步骤2-4。
6. 外层循环结束后,输出count的值。
因为内层循环中j等于5时会执行break语句跳出循环,所以内层循环执行的次数不一定是10次。如果j等于5时不执行break语句,则内层循环将会执行10次,因为j的范围是从0到10。而外层循环总是执行10次,因为i的范围是从1到10,且在i等于5时跳过了本次循环。因此,count的最终值是45,即内层循环执行了45次count++操作。
相关问题
int count = 0; for(int i = 0;i < 100;i++) { count = count++; } System.out.println("count = "+count);
This code will cause an infinite loop because the variable "i" in the for loop is not being incremented. Therefore, the loop condition will always be true and the loop will never end. The count variable is also not being updated in any way, so its value will remain at 0.
If we assume that the increment statement was accidentally left out of the for loop, the corrected code would be:
int count = 0;
for(int i = 0; i < 100; i++) {
count = count + 1;
}
System.out.println("count = " + count);
This code will iterate through the loop 100 times, incrementing the count variable each time. It will then print out the value of count, which should be 100.
c知道打印双色球号码再使用冒泡程序排序后输出 使用void+printNumbers(int+numbers[],+int+count)+{ ++++for+(int+i+=+0;+i+<+count
```c
#include <stdio.h>
void bubbleSort(int numbers[], int count) {
for (int i = 0; i < count - 1; i++) {
for (int j = 0; j < count - i - 1; j++) {
if (numbers[j] > numbers[j + 1]) {
int temp = numbers[j];
numbers[j] = numbers[j + 1];
numbers[j + 1] = temp; }
}
}
}
void printNumbers(int numbers[], int count) {
for (int i = 0; i < count; i++) {
printf("%d ", numbers[i]);
}
printf("\n");
}
int main() {
int numbers[] = {1, 5, 3, 2, 4};
int count = sizeof(numbers) / sizeof(numbers[0]);
printf("Before sorting: ");
printNumbers(numbers, count);
bubbleSort(numbers, count);
printf("After sorting: ");
printNumbers(numbers, count);
return 0;
}
```
运行结果:
Before sorting: 1 5 3 2 4
After sorting: 1 2 3 4 5
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