$(IMAGE_LST): $(IMAGE_FILE) +$(call if_changed,gen-IMAGE_LST)

这是一个Makefile中的规则，目的是生成一个名为$(IMAGE_LST)的文件，依赖于$(IMAGE_FILE)文件。当$(IMAGE_FILE)发生变化时，会执行gen-IMAGE_LST的命令来生成$(IMAGE_LST)文件。'+'符号表示即使Makefile没有开启增量构建模式，也会执行该命令。$(call if_changed,gen-IMAGE_LST)是Makefile中的函数调用，它会将命令行参数'gen-IMAGE_LST'传递给if_changed函数，并执行该函数返回的命令。if_changed是Makefile中的内置函数，它的作用是比较目标文件和依赖文件的时间戳，如果依赖文件的时间戳比目标文件新，就执行if_changed函数中传递的命令。

相关问题

def show(): # 显示所有学生信息 stu_lst = [] if os.path.exists(filename): with open(filename, 'r', encoding = 'UTF-8') as r_file: stu = r_file.readlines() for i in stu: stu_lst.append(eval(i)) if stu_lst: show_stu(stu_lst) else: print('\n暂未保存过数据！')写出上面这段代码的伪代码

定义函数show，没有输入参数
定义空列表stu_lst
如果文件存在，则打开文件
将文件内容按行读入到列表stu中
遍历stu列表中的每个元素i，使用eval函数将其转换为字典类型，添加到stu_lst列表中
如果stu_lst列表不为空，则调用show_stu函数，展示学生信息
否则，提示暂未保存过数据

Create a function pixel_flip(lst, orig_lst, budget, results, i=0) that uses recursion to generate all possible new unique images from the input orig_lst, following these rules: • The input lst is the current list being processed. Initially, this will be the same as orig_lst which is the original flattened image. • The input budget represents the number of pixels that can still be flipped. When the budget reaches 0, no more pixels can be flipped. • The input results is a list of resulting flattened images with flipped pixels. Initially, this will be an empty list. • The input i represents the index of the pixel being processed, by default set to 0, which is used to drive the recursive function towards its base case (i.e., initially starting from i=0). At termination of the function, the argument results should contain all possibilities of the input orig_lst by only flipping pixels from 0 to 1 under both the budget and the adjacency constraints. fill code at #TODO def pixel_flip(lst: list[int], orig_lst: list[int], budget: int, results: list, i: int = 0) -> None: """ Uses recursion to generate all possibilities of flipped arrays where a pixel was a 0 and there was an adjacent pixel with the value of 1. :param lst: 1D list of integers representing a flattened image . :param orig_lst: 1D list of integers representing the original flattened image. :param budget: Integer representing the number of pixels that can be flipped . :param results: List of 1D lists of integers representing all possibilities of flipped arrays， initially empty. :param i: Integer representing the index of the pixel in question. :return: None. """ #TODO def check_adjacent_for_one(flat_image: list[int], flat_pixel: int) -> bool: """ Checks if a pixel has an adjacent pixel with the value of 1. :param flat_image: 1D list of integers representing a flattened image . :param flat_pixel: Integer representing the index of the pixel in question. :return: Boolean. """ #TODO

Here's the code for the pixel_flip function and check_adjacent_for_one helper function:

def pixel_flip(lst: list[int], orig_lst: list[int], budget: int, results: list, i: int = 0) -> None:
    """
    Uses recursion to generate all possibilities of flipped arrays where
    a pixel was a 0 and there was an adjacent pixel with the value of 1.
    :param lst: 1D list of integers representing a flattened image.
    :param orig_lst: 1D list of integers representing the original flattened image.
    :param budget: Integer representing the number of pixels that can be flipped.
    :param results: List of 1D lists of integers representing all possibilities of flipped arrays， initially empty.
    :param i: Integer representing the index of the pixel in question.
    :return: None.
    """
    if budget == 0:
        # Base case: no more pixels can be flipped
        results.append(lst)
        return
    if i >= len(lst):
        # Base case: all pixels have been checked
        return
    if lst[i] == 0 and check_adjacent_for_one(orig_lst, i):
        # Flip the current pixel and recurse with a lower budget
        new_lst = lst.copy()
        new_lst[i] = 1
        pixel_flip(new_lst, orig_lst, budget - 1, results, i + 1)
    # Recurse without flipping the current pixel
    pixel_flip(lst, orig_lst, budget, results, i + 1)

def check_adjacent_for_one(flat_image: list[int], flat_pixel: int) -> bool:
    """
    Checks if a pixel has an adjacent pixel with the value of 1.
    :param flat_image: 1D list of integers representing a flattened image.
    :param flat_pixel: Integer representing the index of the pixel in question.
    :return: Boolean.
    """
    row_size = int(len(flat_image)**0.5)
    row = flat_pixel // row_size
    col = flat_pixel % row_size
    if row > 0 and flat_image[(row-1)*row_size+col] == 1:
        return True
    if row < row_size-1 and flat_image[(row+1)*row_size+col] == 1:
        return True
    if col > 0 and flat_image[row*row_size+(col-1)] == 1:
        return True
    if col < row_size-1 and flat_image[row*row_size+(col+1)] == 1:
        return True
    return False

The pixel_flip function takes in the current list being processed, orig_lst which is the original flattened image, budget representing the number of pixels that can still be flipped, results which is initially an empty list of resulting flattened images with flipped pixels, and i representing the index of the pixel being processed.

The function uses recursion to generate all possibilities of flipped arrays where a pixel was a 0 and there was an adjacent pixel with the value of 1. It first checks if the budget is 0 or if all pixels have been checked, and returns accordingly. If the current pixel is 0 and has an adjacent pixel with the value of 1, it flips the current pixel and recurses with a lower budget. Otherwise, it recurses without flipping the current pixel.

The check_adjacent_for_one helper function takes in the flattened image and the index of the pixel in question, and checks if the pixel has an adjacent pixel with the value of 1. It calculates the row and column of the pixel using integer division and modulus, and checks if the adjacent pixels in the vertical and horizontal directions have the value of 1. If any of the adjacent pixels have the value of 1, it returns True, otherwise it returns False.