【问题描述】列表 ls 中存储了我国 39 所 985 高校所对应的学校类型，请以这个列表为数据变量，编写 代码，统计输出各类型的数量，要求按类别字母顺序输出。 ls = ["Comprehensive", "Polytechnic", "Comprehensive", "Comprehensive", "Comprehensive", \ "Comprehensive", "Comprehensive", "Comprehensive", "Comprehensive", "Comprehensive",\ "Normal", "Polytechnic", "Comprehensive", "Polytechnic", "Comprehensive", "Comprehensive", \ "Comprehensive", "Comprehensive", "Comprehensive","Polytechnic",\ "Polytechnic", "Polytechnic", "Polytechnic", "Normal", "Comprehensive", \ "Agricultural and Forestry", "Polytechnic", "Comprehensive", "Polytechnic", "Polytechnic", \ "Polytechnic", "Comprehensive", "Polytechnic", "Comprehensive", "Comprehensive", \ "Polytechnic", "Agricultural and Forestry", "Nationalities", "Military"] 【样例输入】 无 【样例输出】 Agricultural and Forestry 2 Comprehensive 20 Military 1 Nationalities 1 Normal 2 Polytechnic 13用python写

ls = ["Comprehensive", "Polytechnic", "Comprehensive", "Comprehensive", "Comprehensive",
      "Comprehensive", "Comprehensive", "Comprehensive", "Comprehensive", "Comprehensive",
      "Normal", "Polytechnic", "Comprehensive", "Polytechnic", "Comprehensive", "Comprehensive",
      "Comprehensive", "Comprehensive", "Comprehensive","Polytechnic",
      "Polytechnic", "Polytechnic", "Polytechnic", "Normal", "Comprehensive",
      "Agricultural and Forestry", "Polytechnic", "Comprehensive", "Polytechnic", "Polytechnic",
      "Polytechnic", "Comprehensive", "Polytechnic", "Comprehensive", "Comprehensive",
      "Polytechnic", "Agricultural and Forestry", "Nationalities", "Military"]

count = {}
for school in ls:
    if school in count:
        count[school] += 1
    else:
        count[school] = 1

for key in sorted(count.keys()):
    print(key, count[key])