C语言写一个数独游戏，并实现

好的，我可以为您提供一个简单的数独游戏的代码实现，具体如下：

#include <stdio.h>
#include <stdbool.h>

#define SIZE 9

int board[SIZE][SIZE] = {
    {0, 0, 0, 0, 0, 0, 0, 0, 0},
    {0, 0, 0, 0, 0, 0, 0, 0, 0},
    {0, 0, 0, 0, 0, 0, 0, 0, 0},
    {0, 0, 0, 0, 0, 0, 0, 0, 0},
    {0, 0, 0, 0, 0, 0, 0, 0, 0},
    {0, 0, 0, 0, 0, 0, 0, 0, 0},
    {0, 0, 0, 0, 0, 0, 0, 0, 0},
    {0, 0, 0, 0, 0, 0, 0, 0, 0},
    {0, 0, 0, 0, 0, 0, 0, 0, 0}
};

void print_board() {
    int i, j;
    for (i = 0; i < SIZE; i++) {
        for (j = 0; j < SIZE; j++) {
            printf("%d ", board[i][j]);
        }
        printf("\n");
    }
}

bool is_valid(int row, int col, int num) {
    int i, j;
    // 检查行和列
    for (i = 0; i < SIZE; i++) {
        if (board[row][i] == num || board[i][col] == num) {
            return false;
        }
    }
    // 检查 3x3 方格
    int row_start = (row / 3) * 3;
    int col_start = (col / 3) * 3;
    for (i = row_start; i < row_start + 3; i++) {
        for (j = col_start; j < col_start + 3; j++) {
            if (board[i][j] == num) {
                return false;
            }
        }
    }
    return true;
}

bool solve() {
    int row, col, num;
    for (row = 0; row < SIZE; row++) {
        for (col = 0; col < SIZE; col++) {
            if (board[row][col] == 0) {
                for (num = 1; num <= 9; num++) {
                    if (is_valid(row, col, num)) {
                        board[row][col] = num;
                        if (solve()) {
                            return true;
                        } else {
                            board[row][col] = 0;
                        }
                    }
                }
                return false;
            }
        }
    }
    return true;
}

int main() {
    // 设置数独终盘
    board[0][0] = 5;
    board[0][1] = 3;
    board[0][4] = 7;
    board[1][0] = 6;
    board[1][3] = 1;
    board[1][4] = 9;
    board[1][5] = 5;
    board[2][1] = 9;
    board[2][2] = 8;
    board[2][7] = 6;
    board[3][0] = 8;
    board[3][4] = 6;
    board[3][8] = 3;
    board[4][0] = 4;
    board[4][3] = 8;
    board[4][5] = 3;
    board[4][8] = 1;
    board[5][0] = 7;
    board[5][4] = 2;
    board[5][8] = 6;
    board[6][1] = 6;
    board[6][6] = 2;
    board[6][7] = 8;
    board[7][3] = 4;
    board[7][4] = 1;
    board[7][5] = 9;
    board[7][8] = 5;
    board[8][4] = 8;
    board[8][7] = 7;
    board[8][8] = 9;

    // 打印初始数独
    printf("Initial board:\n");
    print_board();

    // 解数独
    if (solve()) {
        printf("Solved board:\n");
        print_board();
    } else {
        printf("No solution found.\n");
    }

    return 0;
}

这个程序实现了一个简单的数独游戏，使用了递归的方式解决数独问题。您可以先将终盘的数字修改，尝试自己解决数独，或者可以修改程序实现生成数独、计时等功能。