帮我写一个简单的ubus通信例子
时间: 2023-07-31 22:09:20 浏览: 172
好的,以下是一个简单的ubus通信例子:
1. 首先需要在代码中引入相关的头文件:
```
#include <libubox/uloop.h>
#include <libubus.h>
```
2. 初始化ubus连接:
```
struct ubus_context *ctx = NULL;
struct blob_buf b = { 0 };
/* Initialize the ubus context */
ctx = ubus_connect(NULL);
if (!ctx) {
fprintf(stderr, "Failed to connect to ubus\n");
return -1;
}
/* Add the message handler */
ubus_add_uloop(ctx);
/* Prepare a message buffer */
blob_buf_init(&b, 0);
```
3. 发送ubus请求:
```
int ret;
uint32_t id;
/* Prepare the message */
blobmsg_add_string(&b, "message", "Hello, ubus!");
/* Send the message */
ret = ubus_lookup_id(ctx, "my_service", &id);
if (ret != UBUS_STATUS_OK) {
fprintf(stderr, "Failed to lookup ubus object\n");
goto out;
}
ret = ubus_invoke(ctx, id, "my_method", b.head, NULL, NULL, 3000);
if (ret != UBUS_STATUS_OK) {
fprintf(stderr, "Failed to invoke ubus method\n");
}
out:
blob_buf_free(&b);
```
4. 注册ubus服务:
```
static int my_method_handler(struct ubus_context *ctx, struct ubus_object *obj,
struct ubus_request_data *req, const char *method,
struct blob_attr *msg)
{
printf("Received ubus message: %s\n", blobmsg_get_string(msg));
return UBUS_STATUS_OK;
}
static const struct ubus_method my_methods[] = {
{ .name = "my_method", .handler = my_method_handler },
{}
};
static struct ubus_object_type my_object_type =
UBUS_OBJECT_TYPE("my_object", my_methods);
static struct ubus_object my_object = {
.name = "my_service",
.type = &my_object_type,
.methods = my_methods,
.n_methods = ARRAY_SIZE(my_methods),
};
...
/* Register the ubus object */
ret = ubus_add_object(ctx, &my_object);
if (ret) {
fprintf(stderr, "Failed to add ubus object\n");
goto out;
}
/* Run the event loop */
uloop_run();
out:
ubus_free(ctx);
```
以上代码示例中,我们首先初始化了ubus连接并添加了ubus消息处理器。然后我们发送了一个带有"Hello, ubus!"字符串的ubus请求给名为"my_service"的ubus服务的"my_method"方法。最后,我们注册了一个名为"my_service"的ubus服务,并添加了一个名为"my_method"的ubus方法,该方法会在接收到ubus请求时被调用。最后,我们运行了ubus的事件循环。
希望这个例子能对你有所帮助!
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