用%d格式输出10以内阶乘的和
时间: 2023-06-16 09:06:12 浏览: 49
下面是使用 C 语言实现的代码:
```c
#include <stdio.h>
int main() {
int i, j, factorial, sum = 0;
for (i = 1; i <= 10; i++) {
factorial = 1;
for (j = 1; j <= i; j++) {
factorial *= j;
}
sum += factorial;
}
printf("10以内阶乘的和为:%d\n", sum);
return 0;
}
```
输出结果为:
```
10以内阶乘的和为:4037913
```
相关问题
用%d的格式输出10以内阶乘的和1!+2!+。。。=
1! + 2! + ... + 10! = 1 + 2 + 6 + 24 + 120 + 720 + 5040 + 40320 + 362880 + 3628800 = 4037913
以下是使用C语言的代码实现:
```c
#include <stdio.h>
int main() {
int i, j, fact, sum = 0;
for (i = 1; i <= 10; i++) {
fact = 1;
for (j = 1; j <= i; j++) {
fact *= j;
}
sum += fact;
}
printf("1! + 2! + ... + 10! = %d", sum);
return 0;
}
```
输出结果为:1! + 2! + ... + 10! = 4037913
Python用%d的格式输出10以内阶乘的和1!+2!+。。。=
可以使用循环和递归两种方法来实现。以下是两种方法的示例代码:
使用循环:
```python
total = 0
factorial = 1
for i in range(1, 11):
factorial *= i
total += factorial
print("%d! = %d" % (i, factorial))
print("1!+2!+...+10! = %d" % total)
```
使用递归:
```python
def factorial(n):
if n == 0 or n == 1:
return 1
else:
return n * factorial(n-1)
total = 0
for i in range(1, 11):
total += factorial(i)
print("%d! = %d" % (i, factorial(i)))
print("1!+2!+...+10! = %d" % total)
```
输出结果应为:
```
1! = 1
2! = 2
3! = 6
4! = 24
5! = 120
6! = 720
7! = 5040
8! = 40320
9! = 362880
10! = 3628800
1!+2!+...+10! = 4037913
```