SELECT unit.*, COALESCE(sum(detail.order_money), 0) as order_amount, COALESCE(sum(detail.one_commission), 0) as one_commission, COALESCE(sum(detail.two_commission), 0) as two_commission, COALESCE((sum(detail.two_commission) + sum(detail.one_commission)), 0) as total_commission FROM profit_dividend_unit unit LEFT OUTER JOIN profit_dividend_detail detail ON unit.dividend_code = detail.dividend_code GROUP BY unit.unit_id 这个不使用GROUP BY，怎么写？

如果不使用 GROUP BY 子句，则可以使用子查询来实现相同的结果。例如：

SELECT unit.*,
(SELECT COALESCE(SUM(order_money), 0) FROM profit_dividend_detail WHERE dividend_code = unit.dividend_code) as order_amount,
(SELECT COALESCE(SUM(one_commission), 0) FROM profit_dividend_detail WHERE dividend_code = unit.dividend_code) as one_commission,
(SELECT COALESCE(SUM(two_commission), 0) FROM profit_dividend_detail WHERE dividend_code = unit.dividend_code) as two_commission,
(SELECT COALESCE(SUM(one_commission), 0) + COALESCE(SUM(two_commission), 0) FROM profit_dividend_detail WHERE dividend_code = unit.dividend_code) as total_commission
FROM profit_dividend_unit unit;

该语句将返回与原始查询相同的结果，但是使用了子查询来替代 GROUP BY 子句。

相关问题

SELECT unit.*, sum( detail.order_money ) order_amount, sum( detail.one_commission ) one_commission, sum( detail.two_commission ) two_commission, ( sum( detail.two_commission ) + sum( detail.one_commission ) ) AS total_commission FROM profit_dividend_unit unit LEFT JOIN profit_dividend_detail detail ON unit.dividend_code = detail.dividend_code 修改改条sql，需要左表全部数据，没有对应的右表字段则显示空

可以使用 `LEFT OUTER JOIN`，同时使用 `COALESCE` 函数来将没有对应的右表字段显示为空。

修改后的 SQL 如下所示：

SELECT unit.*, 
       COALESCE(sum(detail.order_money), 0) as order_amount, 
       COALESCE(sum(detail.one_commission), 0) as one_commission, 
       COALESCE(sum(detail.two_commission), 0) as two_commission, 
       COALESCE((sum(detail.two_commission) + sum(detail.one_commission)), 0) as total_commission
FROM profit_dividend_unit unit 
LEFT OUTER JOIN profit_dividend_detail detail ON unit.dividend_code = detail.dividend_code 
GROUP BY unit.unit_id

在这个修改后的 SQL 中，我们使用了 `COALESCE` 函数，将可能为空的字段替换成了 0，确保了结果集中每一列都有值。同时，我们也保留了左表的全部数据，即使在右表中没有对应的记录。

纠错 select COALESCE(ooc.second_amount,1) /COALESCE(ooc.unit_quantity,1) as cc from ods.ods_durian_loading_task odlt left join ods.ods_durian_loading_sku_item odlsi on odlsi.plan_id=odlt.plan_id left join ods.ods_oms_commodity ooc on ooc.id=odlsi.commodity_id;

这个SQL语句中的COALESCE函数参数看起来是正确的，但是在除法运算符之前使用了不必要的空格。请尝试修改查询，将除法运算符和其前面的空格删除，如下所示：

select COALESCE(ooc.second_amount, 1) / COALESCE(ooc.unit_quantity, 1) as cc 
from ods.ods_durian_loading_task odlt 
left join ods.ods_durian_loading_sku_item odlsi on odlsi.plan_id = odlt.plan_id 
left join ods.ods_oms_commodity ooc on ooc.id = odlsi.commodity_id;

如果您仍然遇到问题，请提供更多上下文或错误信息。