SELECT f.FAULT_CODE AS "异常代码", f.FAULT_NAME AS "异常名称", COALESCE(r.REPORT_DEPT_CODE, 'N/A') AS "反馈部门", COUNT(r.REPORT_DEPT_CODE) AS "反馈次数", (SELECT COUNT(*) FROM FAULT_REPORT d WHERE d.FAULT_CODE = f.FAULT_CODE) AS "合计反馈次数" FROM FAULT_TYPE f LEFT JOIN FAULT_REPORT r ON f.FAULT_CODE = r.FAULT_CODE WHERE f.BUILT_IN_FLAG = 1 GROUP BY f.FAULT_CODE,f.FAULT_NAME, COALESCE(r.REPORT_DEPT_CODE, 'N/A') ORDER BY f.FAULT_CODE在ORACLE中把此查询SQL用union all在异常代码下加一个009编码并且异常名称下加上合计字段

在ORACLE中，将此查询SQL用union all在异常代码下加一个009编码并且异常名称下加上合计字段的方法如下：

SELECT f.FAULT_CODE AS "异常代码", 
       f.FAULT_NAME AS "异常名称", 
       COALESCE(r.REPORT_DEPT_CODE, 'N/A') AS "反馈部门", 
       COUNT(r.REPORT_DEPT_CODE) AS "反馈次数", 
       (SELECT COUNT(*) FROM FAULT_REPORT d WHERE d.FAULT_CODE = f.FAULT_CODE) AS "合计反馈次数" 
FROM FAULT_TYPE f 
LEFT JOIN FAULT_REPORT r ON f.FAULT_CODE = r.FAULT_CODE 
WHERE f.BUILT_IN_FLAG = 1 
GROUP BY f.FAULT_CODE,f.FAULT_NAME, COALESCE(r.REPORT_DEPT_CODE, 'N/A') 
UNION ALL
SELECT '009' AS "异常代码", 
       '合计' AS "异常名称", 
       'N/A' AS "反馈部门", 
       COUNT(*) AS "反馈次数", 
       SUM((SELECT COUNT(*) FROM FAULT_REPORT d WHERE d.FAULT_CODE = f.FAULT_CODE)) AS "合计反馈次数" 
FROM FAULT_TYPE f 
LEFT JOIN FAULT_REPORT r ON f.FAULT_CODE = r.FAULT_CODE 
WHERE f.BUILT_IN_FLAG = 1 
GROUP BY f.FAULT_CODE,f.FAULT_NAME 
ORDER BY "异常代码";

在上述SQL语句中，使用UNION ALL操作符将原始查询结果与新增的结果集合并。新增结果集的异常代码为009，异常名称为合计，反馈部门为N/A。同时，使用SUM和子查询的组合，计算出所有异常代码的合计反馈次数，并在查询结果中添加一个合计反馈次数的列。最后，按异常代码进行排序。