21点游戏python
时间: 2023-08-27 09:05:13 浏览: 40
这里是一个简单的21点游戏的Python代码:
```python
import random
def deal_card():
"""随机发一张牌"""
cards = [11,2,3,4,5,6,7,8,9,10,10,10,10]
return random.choice(cards)
def calculate_score(cards):
"""计算手牌分数"""
if sum(cards) == 21 and len(cards) == 2:
return 0
if 11 in cards and sum(cards) > 21:
cards.remove(11)
cards.append(1)
return sum(cards)
def compare(user_score, computer_score):
"""比较分数"""
if user_score == computer_score:
return "平局"
elif computer_score == 0:
return "你输了,对方获胜!"
elif user_score == 0:
return "你赢了,恭喜!"
elif user_score > 21:
return "你爆了,对方获胜!"
elif computer_score > 21:
return "对方爆了,你赢了!"
elif user_score > computer_score:
return "你赢了,恭喜!"
else:
return "你输了,对方获胜!"
def play_game():
"""玩21点游戏"""
print("欢迎来到21点游戏!")
user_cards = []
computer_cards = []
is_game_over = False
for _ in range(2):
user_cards.append(deal_card())
computer_cards.append(deal_card())
while not is_game_over:
user_score = calculate_score(user_cards)
computer_score = calculate_score(computer_cards)
print(f"你的牌:{user_cards},当前分数为:{user_score}")
print(f"对方的牌:[{computer_cards[0]},X]")
if user_score == 0 or computer_score == 0 or user_score > 21:
is_game_over = True
else:
user_choice = input("是否要再拿一张牌?(y/n)").lower()
if user_choice == "y":
user_cards.append(deal_card())
else:
is_game_over = True
while computer_score != 0 and computer_score < 17:
computer_cards.append(deal_card())
computer_score = calculate_score(computer_cards)
print(f"你的牌:{user_cards},最终分数为:{user_score}")
print(f"对方的牌:{computer_cards},最终分数为:{computer_score}")
print(compare(user_score, computer_score))
while input("是否要玩一局21点游戏?(y/n)").lower() == "y":
play_game()
```
这个代码实现了一个简单的21点游戏,每次随机发牌,计算手牌分数,并且可以让玩家选择是否再拿一张牌。最终比较双方分数,输出胜负结果。