java求最大公因数,最小公倍数
时间: 2023-05-12 11:02:52 浏览: 94
求最大公因数可以使用辗转相除法,代码如下:
public static int gcd(int a, int b) {
if (b == 0) {
return a;
}
return gcd(b, a % b);
}
求最小公倍数可以使用最大公因数,代码如下:
public static int lcm(int a, int b) {
return a * b / gcd(a, b);
}
相关问题
java求最大公因数最小公倍数
以下是使用Java求最大公因数和最小公倍数的方法:
```java
public class GCDandLCM {
// 求最大公因数
public static int gcd(int a, int b) {
while (b != 0) {
int temp = a % b;
a = b;
b = temp;
}
return a;
}
// 求最小公倍数
public static int lcm(int a, int b) {
return a * b / gcd(a, b);
}
public static void main(String[] args) {
int num1 = 2;
int num2 = 27;
int gcdResult = gcd(num1, num2);
int lcmResult = lcm(num1, num2);
System.out.println("最大公因数: " + gcdResult); // 输出:1
System.out.println("最小公倍数: " + lcmResult); // 输出:54
}
}
```
java求最大公因数和最小公倍数
求最大公因数和最小公倍数可以使用辗转相除法,代码如下:
```
public class GCDAndLCM {
public static void main(String[] args) {
int a = 24, b = 36;
int gcd = gcd(a, b);
int lcm = lcm(a, b);
System.out.println("最大公因数:" + gcd);
System.out.println("最小公倍数:" + lcm);
}
// 求最大公因数
public static int gcd(int a, int b) {
if (b == 0) {
return a;
}
return gcd(b, a % b);
}
// 求最小公倍数
public static int lcm(int a, int b) {
return a * b / gcd(a, b);
}
}
```
输出结果为:
```
最大公因数:12
最小公倍数:72
```
希望能帮到你!
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