上面的需求怎么样java实现?
时间: 2023-10-17 20:14:51 浏览: 29
以下是一个可能的 Java 实现,包含了题目中的三个功能:
```java
import java.util.ArrayList;
import java.util.List;
import java.util.Random;
public class GradingSystem {
private static final int NUM_STUDENTS = 100;
private static final int NUM_TEACHERS = 3;
private static final int NUM_BLOCKS = 4;
private static final int BLOCK_SIZE = 100;
private static class Task {
int block;
int teacher;
boolean completed;
Task(int block, int teacher) {
this.block = block;
this.teacher = teacher;
this.completed = false;
}
}
private static List<Task> tasks;
public static void main(String[] args) {
tasks = new ArrayList<>();
for (int i = 0; i < NUM_BLOCKS; i++) {
for (int j = 0; j < NUM_TEACHERS; j++) {
tasks.add(new Task(i, j));
}
}
// 统计每个老师的任务总数
int[] numTasksPerTeacher = new int[NUM_TEACHERS];
for (Task task : tasks) {
numTasksPerTeacher[task.teacher]++;
}
System.out.println("每个老师的任务总数为:" + java.util.Arrays.toString(numTasksPerTeacher));
// 双评功能
for (Task task : tasks) {
if (task.completed) {
continue;
}
int[] candidates = new int[NUM_TEACHERS];
int numCandidates = 0;
for (int i = 0; i < NUM_TEACHERS; i++) {
if (numTasksPerTeacher[i] < 2) {
candidates[numCandidates++] = i;
}
}
if (numCandidates < 2) {
continue; // 该题块的批改人数不足 2,跳过
}
Random random = new Random();
int i = random.nextInt(numCandidates);
int j = random.nextInt(numCandidates - 1);
if (j >= i) {
j++; // 避免重复选择同一个老师
}
task.teacher = candidates[i];
tasks.get(getTaskIndex(task.block, candidates[j])).teacher = candidates[j];
task.completed = true;
tasks.get(getTaskIndex(task.block, candidates[j])).completed = true;
numTasksPerTeacher[candidates[i]]++;
numTasksPerTeacher[candidates[j]]++;
}
System.out.println("双评功能完成后每个老师的任务总数为:" + java.util.Arrays.toString(numTasksPerTeacher));
// 多评功能
for (Task task : tasks) {
if (task.completed) {
continue;
}
int[] candidates = new int[NUM_TEACHERS];
int numCandidates = 0;
for (int i = 0; i < NUM_TEACHERS; i++) {
if (numTasksPerTeacher[i] < 3) {
candidates[numCandidates++] = i;
}
}
if (numCandidates < 3) {
continue; // 该题块的批改人数不足 3,跳过
}
Random random = new Random();
int i = random.nextInt(numCandidates);
int j = random.nextInt(numCandidates - 1);
int k = random.nextInt(numCandidates - 2);
if (j >= i) {
j++; // 避免重复选择同一个老师
}
if (k >= i) {
k++; // 避免重复选择同一个老师
}
if (k >= j) {
k++; // 避免重复选择同一个老师
}
task.teacher = candidates[i];
tasks.get(getTaskIndex(task.block, candidates[j])).teacher = candidates[j];
tasks.get(getTaskIndex(task.block, candidates[k])).teacher = candidates[k];
task.completed = true;
tasks.get(getTaskIndex(task.block, candidates[j])).completed = true;
tasks.get(getTaskIndex(task.block, candidates[k])).completed = true;
numTasksPerTeacher[candidates[i]]++;
numTasksPerTeacher[candidates[j]]++;
numTasksPerTeacher[candidates[k]]++;
}
System.out.println("多评功能完成后每个老师的任务总数为:" + java.util.Arrays.toString(numTasksPerTeacher));
}
private static int getTaskIndex(int block, int teacher) {
return block * NUM_TEACHERS + teacher;
}
}
```
上述代码中,`Task` 类表示一个批改任务,包含题块编号、阅卷老师编号和是否已完成等信息。`tasks` 列表存储所有批改任务。在程序开始时,根据题目要求生成所有的批改任务,即每个题块的每个老师都需要批改一次。
首先通过遍历 `tasks` 列表和 `numTasksPerTeacher` 数组统计每个老师的任务总数。然后实现双评功能,对于每个未完成的批改任务,随机选择两名未完成该题块批改的老师进行分配,直到每个题块的批改人数均为 2。最后实现多评功能,对于每个未完成的批改任务,将该题块的批改任务分配给所有未完成该题块批改的老师,直到每个题块的批改人数均为 3。
在实现过程中,还需要实现一个 `getTaskIndex` 方法,用于计算某个题块和老师对应的批改任务在 `tasks` 列表中的下标。