用Java写一个布谷鸟过滤器
时间: 2024-05-13 09:17:24 浏览: 7
布谷鸟过滤器是一种基于哈希表的快速过滤算法,用于判断一个元素是否存在于一个集合中。下面是一个简单的 Java 实现:
```java
import java.util.BitSet;
public class CuckooFilter {
private final int capacity;
private final int fingerprintSize;
private final int maxNumKicks;
private final BitSet bitSet;
private final int[] fingerprints;
public CuckooFilter(int capacity, int fingerprintSize, int maxNumKicks) {
this.capacity = capacity;
this.fingerprintSize = fingerprintSize;
this.maxNumKicks = maxNumKicks;
this.bitSet = new BitSet(capacity);
this.fingerprints = new int[capacity];
}
private int getHash1(String key) {
return key.hashCode() % capacity;
}
private int getHash2(int hash1, String key) {
return (hash1 ^ key.hashCode()) % capacity;
}
private int getFingerprint(String key) {
int hash = key.hashCode();
hash ^= (hash >>> 20) ^ (hash >>> 12);
return hash ^ (hash >>> 7) ^ (hash >>> 4) & ((1 << fingerprintSize) - 1);
}
private int getAlternativeIndex(int index, int fingerprint) {
return (index ^ (fingerprint * 0x5bd1e995)) % capacity;
}
public boolean insert(String key) {
int hash1 = getHash1(key);
int hash2 = getHash2(hash1, key);
int fingerprint = getFingerprint(key);
for (int i = 0; i < maxNumKicks; i++) {
int index = (i % 2 == 0) ? hash1 : hash2;
int altIndex = getAlternativeIndex(index, fingerprint);
if (bitSet.get(index)) {
int oldFingerprint = fingerprints[index];
fingerprints[index] = fingerprint;
fingerprint = oldFingerprint;
index = altIndex;
} else {
bitSet.set(index);
fingerprints[index] = fingerprint;
return true;
}
}
return false;
}
public boolean contains(String key) {
int hash1 = getHash1(key);
int hash2 = getHash2(hash1, key);
int fingerprint = getFingerprint(key);
int index1 = hash1;
int index2 = hash2;
if (bitSet.get(index1) && fingerprints[index1] == fingerprint) {
return true;
} else if (bitSet.get(index2) && fingerprints[index2] == fingerprint) {
return true;
} else {
int altIndex = getAlternativeIndex(index1, fingerprint);
if (bitSet.get(altIndex) && fingerprints[altIndex] == fingerprint) {
return true;
} else {
altIndex = getAlternativeIndex(index2, fingerprint);
if (bitSet.get(altIndex) && fingerprints[altIndex] == fingerprint) {
return true;
}
}
}
return false;
}
}
```
这个实现中使用了两个哈希函数来计算两个可能的索引位置。如果第一个位置已经被占用,就把对应的元素踢出去,然后将新元素放到对应的位置。如果第二个位置已经被占用,就重复这个过程,直到达到最大迭代次数为止。