从前一题生成的data1.txt文件中读取数据至二维列表 要求计算二维列表所有四周元素的累加和
时间: 2024-05-03 20:18:48 浏览: 10
好的,可以按照以下步骤来读取文件并计算累加和:
1. 打开文件并读取内容:
```python
with open("data1.txt", "r") as f:
content = f.read()
```
2. 将每一行的数字分割成列表,再将这些列表组成一个二维列表:
```python
rows = content.strip().split("\n")
lst = [list(map(int, row.split())) for row in rows]
```
3. 计算每个元素四周的累加和,并存储在一个新的二维列表中:
```python
# 初始化新的二维列表
sum_lst = [[0 for _ in range(len(lst[0]))] for _ in range(len(lst))]
# 遍历原始二维列表
for i in range(len(lst)):
for j in range(len(lst[0])):
# 计算当前元素四周的累加和
total = 0
if i > 0:
total += lst[i-1][j]
if i < len(lst)-1:
total += lst[i+1][j]
if j > 0:
total += lst[i][j-1]
if j < len(lst[0])-1:
total += lst[i][j+1]
sum_lst[i][j] = total
```
4. 输出累加和二维列表:
```python
for row in sum_lst:
print(row)
```
完整代码如下:
```python
with open("data1.txt", "r") as f:
content = f.read()
rows = content.strip().split("\n")
lst = [list(map(int, row.split())) for row in rows]
sum_lst = [[0 for _ in range(len(lst[0]))] for _ in range(len(lst))]
for i in range(len(lst)):
for j in range(len(lst[0])):
total = 0
if i > 0:
total += lst[i-1][j]
if i < len(lst)-1:
total += lst[i+1][j]
if j > 0:
total += lst[i][j-1]
if j < len(lst[0])-1:
total += lst[i][j+1]
sum_lst[i][j] = total
for row in sum_lst:
print(row)
```