用verilog写一个除法器
时间: 2023-05-15 19:04:59 浏览: 127
除法器的Verilog实现
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好的,以下是一个简单的 Verilog 除法器的代码示例:
module divider(input [31:0] dividend, divisor, output [31:0] quotient, remainder);
reg [31:0] dividend_reg;
reg [31:0] divisor_reg;
reg [31:0] quotient_reg;
reg [31:0] remainder_reg;
reg sign;
always @(*) begin
dividend_reg = dividend;
divisor_reg = divisor;
sign = (dividend_reg[31] ^ divisor_reg[31]);
dividend_reg = (sign) ? -dividend_reg : dividend_reg;
divisor_reg = (sign) ? -divisor_reg : divisor_reg;
end
always @(*) begin
quotient_reg = 0;
remainder_reg = dividend_reg;
for (int i = 31; i >= 0; i = i - 1) begin
quotient_reg = quotient_reg << 1;
remainder_reg = remainder_reg << 1;
quotient_reg[0] = (remainder_reg[31] == 1'b1);
remainder_reg[31] = 1'b0;
if (remainder_reg >= divisor_reg) begin
remainder_reg = remainder_reg - divisor_reg;
quotient_reg[0] = 1'b1;
end
end
quotient = (sign) ? -quotient_reg : quotient_reg;
remainder = (sign) ? -remainder_reg : remainder_reg;
end
endmodule
这个除法器使用了 Booth 算法来实现除法运算。它将被除数和除数都转换为正数,然后进行除法运算,最后根据符号位确定商和余数的符号。
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