用python写一段代码读取一个 8 位伪彩色 转化为 24 位真彩色 BMP 文件,最后存储。请用面向对象的方法,不可以使用库
时间: 2024-05-04 08:22:45 浏览: 109
读写8位24位bmp图像
抱歉,我可以回答您的问题,以下是使用 Python 面向对象编写读取8位伪彩色图像转化为24位真彩色BMP文件并存储的代码:
```python
class ImageConverter:
def __init__(self, input_file, output_file):
self.input_file = input_file
self.output_file = output_file
def read_file(self):
with open(self.input_file, 'rb') as file:
# read BMP header
header = file.read(54)
# read image data
data_8bit = file.read()
return header, data_8bit
def convert_color(self, color):
# convert 8-bit color to 24-bit color
r = color & 0xE0
g = (color & 0x1C) << 3
b = (color & 0x03) << 6
return bytes([b, g, r])
def convert_image(self):
header, data_8bit = self.read_file()
# BMP header
width = int.from_bytes(header[18:22], byteorder='little')
height = int.from_bytes(header[22:26], byteorder='little')
bits_per_pixel = int.from_bytes(header[28:30], byteorder='little')
# 8-bit color image size
size_8bit = len(data_8bit)
# 24-bit color image size
size_24bit = height * width * 3
# create BMP header for 24-bit color image
header_24bit = header[:2] + size_24bit.to_bytes(4, byteorder='little') \
+ header[6:10] + (54 - 14).to_bytes(4, byteorder='little') \
+ header[14:26] + (40).to_bytes(4, byteorder='little') \
+ width.to_bytes(4, byteorder='little') \
+ height.to_bytes(4, byteorder='little') \
+ header[34:46] + (0).to_bytes(8, byteorder='little')
# convert 8-bit color data to 24-bit color data
data_24bit = b''
for i in range(0, size_8bit):
data_24bit += self.convert_color(data_8bit[i])
# write BMP header and data
with open(self.output_file, 'wb') as file:
file.write(header_24bit + data_24bit)
if __name__ == '__main__':
input_file = '/path/to/input/file'
output_file = '/path/to/output/file'
converter = ImageConverter(input_file, output_file)
converter.convert_image()
```
请注意,本代码仅适用于8位伪彩色图像并假设输入的8位伪彩色数据行存储,即每一行的数据从左到右排列。
阅读全文