创建文件number.txt，里面存放多个整数 2 读取该文件里面的数据，并统计亚均值，最大值，最小值。 3.将统计的信息及数据排序后 写入result.txt中。 用Java实现

好的，这里是一个Java的实现：

import java.io.BufferedReader;
import java.io.BufferedWriter;
import java.io.FileReader;
import java.io.FileWriter;
import java.io.IOException;
import java.util.ArrayList;
import java.util.Collections;
import java.util.List;

public class FileIOExample {
    public static void main(String[] args) {
        String inputFileName = "number.txt";
        String outputFileName = "result.txt";
        List<Integer> numbers = new ArrayList<>();

        // 1. 读取文件内容并计算平均值、最大值和最小值
        try (BufferedReader reader = new BufferedReader(new FileReader(inputFileName))) {
            String line;
            int sum = 0;
            int count = 0;
            int maxNum = Integer.MIN_VALUE;
            int minNum = Integer.MAX_VALUE;
            while ((line = reader.readLine()) != null) {
                int num = Integer.parseInt(line.trim());
                numbers.add(num);
                sum += num;
                count++;
                maxNum = Math.max(maxNum, num);
                minNum = Math.min(minNum, num);
            }
            double avg = (double) sum / count;

            // 2. 将信息及排序后的结果写入result.txt中
            try (BufferedWriter writer = new BufferedWriter(new FileWriter(outputFileName))) {
                writer.write("平均值：" + avg + "\n");
                writer.write("最大值：" + maxNum + "\n");
                writer.write("最小值：" + minNum + "\n");

                Collections.sort(numbers);
                for (int num : numbers) {
                    writer.write(num + "\n");
                }
            } catch (IOException e) {
                e.printStackTrace();
            }
        } catch (IOException e) {
            e.printStackTrace();
        }
    }
}

代码中的注释已经解释了每一步的实现过程。如果您有其他问题，请随时提出。