爱因斯坦斑马问题Python代码

以下是一个简单的 Python 代码实现爱因斯坦斑马问题的解答：

# 定义问题中的变量和取值范围
colors = ["红色", "绿色", "白色", "黄色", "蓝色"]
nationalities = ["英国人", "西班牙人", "挪威人", "乌克兰人", "日本人"]
pets = ["狗", "蜗牛", "猫", "马", "斑马"]
drinks = ["茶", "橙汁", "牛奶", "咖啡", "水"]
cigarettes = ["玛尔博罗", "温德尔", "混合烟", "幸福", "士马高"]

# 使用嵌套循环生成所有可能的组合
for c1 in colors:
    for c2 in colors:
        if c1 == c2:
            continue
        for n1 in nationalities:
            for n2 in nationalities:
                if n1 == n2:
                    continue
                for p1 in pets:
                    for p2 in pets:
                        if p1 == p2:
                            continue
                        for d1 in drinks:
                            for d2 in drinks:
                                if d1 == d2:
                                    continue
                                for ciga1 in cigarettes:
                                    for ciga2 in cigarettes:
                                        if ciga1 == ciga2:
                                            continue
                                        # 检查所有限制条件是否满足
                                        if n1 == "英国人" and c1 != "红色":
                                            continue
                                        if n2 == "西班牙人" and p2 != "狗":
                                            continue
                                        if p1 == "蜗牛" and c1 != "黄色":
                                            continue
                                        if n1 == "乌克兰人" and ciga1 != "士马高":
                                            continue
                                        if c2 == "绿色" and c1 != "白色" - 1:
                                            continue
                                        if ciga1 == "温德尔" and d1 != "茶":
                                            continue
                                        if p2 == "马" and ciga2 != "玛尔博罗":
                                            continue
                                        if abs(drinks.index(d1) - pets.index(p1)) != 1:
                                            continue
                                        if abs(drinks.index(d2) - ciga2.index(ciga2)) != 1:
                                            continue
                                        # 输出符合条件的解
                                        print("颜色\t国籍\t宠物\t饮料\t香烟")
                                        print("{}\t{}\t{}\t{}\t{}".format(c1, n1, p1, d1, ciga1))
                                        print("{}\t{}\t{}\t{}\t{}".format(c2, n2, p2, d2, ciga2))

这段代码使用了嵌套循环生成了所有可能的组合，并通过逐一检查限制条件来筛选出符合条件的解。最后将符合条件的解输出。