stm32f405rgt6按键控制led4灯亮灭
时间: 2023-09-18 07:14:41 浏览: 48
以下是使用STM32F405RGT6控制LED4灯亮灭的示例代码:
```
#include "stm32f4xx.h"
int main(void)
{
// Enable the GPIOA and GPIOD clock
RCC->AHB1ENR |= RCC_AHB1ENR_GPIOAEN | RCC_AHB1ENR_GPIODEN;
// Configure PA0 as input with pull-up resistor
GPIOA->MODER &= ~GPIO_MODER_MODE0;
GPIOA->PUPDR |= GPIO_PUPDR_PUPD0_0;
// Configure PD12 as output
GPIOD->MODER &= ~GPIO_MODER_MODE12;
GPIOD->MODER |= GPIO_MODER_MODE12_0;
while (1)
{
if (GPIOA->IDR & GPIO_IDR_ID0) // if PA0 is high (button not pressed)
{
GPIOD->BSRR = GPIO_BSRR_BR12; // turn off LED4
}
else // if PA0 is low (button pressed)
{
GPIOD->BSRR = GPIO_BSRR_BS12; // turn on LED4
}
}
}
```
该代码假设您已将按钮连接到PA0引脚,LED4连接到PD12引脚。当按下按钮时,LED4将点亮,松开按钮时,LED4将熄灭。