用python写一遍上面的C++代码
时间: 2024-05-04 10:21:08 浏览: 10
很好,以下是用Python编写的等价代码:
```python
import math
def calculateDistance(x1, y1, x2, y2):
return math.sqrt((x2 - x1) ** 2 + (y2 - y1) ** 2)
x1 = float(input("Enter x1: "))
y1 = float(input("Enter y1: "))
x2 = float(input("Enter x2: "))
y2 = float(input("Enter y2: "))
distance = calculateDistance(x1, y1, x2, y2)
print("The distance between the two points is:", distance)
```
这段代码与上面的C ++代码执行的操作是相同的,但使用了Python语言的语法和函数库。
相关问题
用c++写一遍上述代码,能直接运行
好的,下面是使用 C++ 实现的代码:
```c++
#include <iostream>
#include <vector>
#include <set>
#include <queue>
using namespace std;
int bfs(int start_x, int start_y, int end_x, int end_y) {
queue<vector<int>> q;
q.push({start_x, start_y, 0}); // 将起始位置加入队列
set<pair<int, int>> visited; // 记录已经搜索过的位置
visited.insert({start_x, start_y});
while (!q.empty()) {
vector<int> cur = q.front();
q.pop();
int x = cur[0], y = cur[1], step = cur[2];
if (x == end_x && y == end_y) // 找到目标位置
return step;
// 尝试所有可能的移动方式,并将能够到达的位置加入队列
for (auto [dx, dy] : vector<vector<int>>{{1, 0}, {-1, 0}, {0, 1}, {0, -1}, {2, 0}, {-2, 0}, {0, 2}, {0, -2}, {2, 2}}) {
int nx = x + dx, ny = y + dy;
if (visited.find({nx, ny}) == visited.end() && 1 <= nx && nx <= end_x + end_y && 1 <= ny && ny <= end_x + end_y) {
visited.insert({nx, ny});
q.push({nx, ny, step + 1});
}
}
}
return -1; // 如果无法到达目标位置,返回-1
}
int backtrack(int x, int y, int end_x, int end_y, set<pair<int, int>>& visited, int step) {
if (x == end_x && y == end_y) // 找到目标位置,返回步数
return step;
int min_step = INT_MAX;
for (auto [dx, dy] : vector<vector<int>>{{1, 0}, {-1, 0}, {0, 1}, {0, -1}, {2, 0}, {-2, 0}, {0, 2}, {0, -2}, {2, 2}}) {
int nx = x + dx, ny = y + dy;
if (visited.find({nx, ny}) == visited.end() && 1 <= nx && nx <= end_x + end_y && 1 <= ny && ny <= end_x + end_y) {
visited.insert({nx, ny});
int cur_step = backtrack(nx, ny, end_x, end_y, visited, step + 1);
if (cur_step != -1)
min_step = min(min_step, cur_step);
visited.erase({nx, ny});
}
}
return min_step == INT_MAX ? -1 : min_step;
}
int min_steps(int start_x, int start_y, int end_x, int end_y) {
set<pair<int, int>> visited;
visited.insert({start_x, start_y});
return backtrack(start_x, start_y, end_x, end_y, visited, 0);
}
int main() {
int start_x = 1, start_y = 1, end_x = 5, end_y = 5;
cout << bfs(start_x, start_y, end_x, end_y) << endl; // 输出最小步数
cout << min_steps(start_x, start_y, end_x, end_y) << endl;
return 0;
}
```
其中,backtrack 函数和之前的 Python 版本一样,使用 visited 集合记录已经访问过的位置。bfs 函数使用了一个队列和一个 visited 集合来实现广度优先搜索,代码结构和之前的 Python 版本也相似。注意,C++ 中使用 set 和 pair 来代替 Python 中的集合和元组。
把下面的代码用python语言重新输出一遍
很好,以下是Python语言的代码:
```python
T = int(input())
for _ in range(T):
temp = input().strip()
s1 = []
count = 0
for i in range(len(temp)):
if temp[i] == '{' or temp[i] == '[' or temp[i] == '(':
s1.append(temp[i])
elif not s1:
count = 1
break
elif temp[i] == '}':
if s1[-1] == '{':
s1.pop()
else:
count = 1
break
elif temp[i] == ']':
if s1[-1] == '[':
s1.pop()
else:
count = 1
break
elif temp[i] == ')':
if s1[-1] == '(':
s1.pop()
else:
count = 1
break
if s1:
count = 1
if count == 1:
print("No")
else:
print("Yes")
s1.clear()
```
这段代码与之前的C++代码功能相同,使用了Python的列表来代替了C++中的栈。